Molarity (M) represents the moles of a solute per liter of a solvent. In this case, sucrose is the solute and water is the solvent. First, convert your 125g of sucrose to moles...molar mass of sucrose = 342.34 soo you have .365 moles of sucrose. Since you have exactly one L of solution, the molarity of the solution is .365 M Molarity (M) represents the moles of a solute per liter of a solvent. In this case, sucrose is the solute and water is the solvent. First, convert your 125g of sucrose to moles...molar mass of sucrose = 342.34 soo you have .365 moles of sucrose. Since you have exactly one L of solution, the molarity of the solution is .365 M
You prepare a solution by dissolving a known mass of solute (often a solid) into a specific amount of a solvent. One of the most common ways to express the concentration of the solution is M or molarity, which is moles of solute per liter of solution.
1 % DCPIP solution can be prepared by dissolving 1g of the dye in 100cm3 of water
The Molarity of the solution is .901
You prepare a solution by dissolving a known mass of solute into a specific amount of solvent. In solutions, M is the molarity, or moles of solute per liter of solution. For 300 ml of a 0.1 M Na CL solution from a solid Na CL solution and water you need water and sodium chloride.
See the two Related Questions to the left for the answer.The first is how to prepare a solution starting with a solid substance (and dissolving it). The second question is how to prepare a solution by diluting another solution.
It depends on how much you are trying to make and what you are diluting it from, but the formula for figuring it out is Molarity of starting solution times X (in which X is how much you will be adding) equals Molarity of the solution you are producing times its volume
molisch reagent is prepared by dissolving 5g of alpha napthol in 100 ml alcohol
Normality=Molarity x N-factor. =>Molarity=Normality/N-factor. N-factor for H2SO4 is 2. So, Molarity=0.02/2=0.01 M This means we have to dissolve 0.01moles of H2SO4 in 1L of water t prepare a 0.02 N solution. 0.01 M H2SO4 = 98g/0.01=.98g We dissolve .98g H2SO4 1L of water to get the desired solution
The purpose is to prepare a sample solution for analysis.
Look at the bottle of HCl. It gives a molarity. then dilute to 0.25 M.
The molarity is figured out by the number of moles of NaOH over the number of liters of water. so if the molarity is 0.5M and there is 1.0L of water then there has to be 0.5 moles of NaOH in the solution.
You prepare 0.05mM from NaHC03 by first dissolving it. As you dissolve it in water, monitor the pH of the solution. The Internet does not list anything with the formula ZnSO4.7H20.
moles of KCl=molarity of KCl solution * volume of KCl solution=4.0*1.00=4.0 moles
Hydrochloric acid is prepared by dissolving hydrogen chloride gas in water. Hydrogen chloride is a covalent compound, but when dissolved in water it ionizes to form hydrogen ions and chloride ions as follows: By Kuldeep K. bansal INDIA
Your question does not make sense, an almost infinite amount of solution could be prepared if desired
it has to be prepared using methanol or ethanol at the concentration we required.
You can prepare 250 mL of a 2,5 % solution.
Diluted Ammonia solution can be prepared by diluted strong ammonia solution with the appropriate quantity of purified water.
Molarity = moles of solute/liters of solution or, for our purposes moles of solute = liters of solution * Molarity moles of AgNO3 = 0,50 liters * 4.0 M = 2.0 moles of AgNO3 needed --------------------------------------
Iodine monochloride is soluble in alcohol, ether, acetic acid. ICl is prepared from iodine and chlorine.
See Related Questions to the left "How do you prepare a solution of a specific concentration?"
i think yes by increasing volume tenfold.because 0.01 is greater than 0.1.by diluting 0.01m solution 0.1m can be prepared.
to prepare 1N we have to dilute 40gms of NaOH in 1 litre of water as for NaOH normality =molarity so to prepare 0.1N NaOH we have to dilute 4gms of NaOH in 1 litre of water..