The equivalent of 125 g zinc is 1, 91 moles.
3,80 g Zn have 0,058 moles.
The answer is 0,058 moles.
Balanced equation first.Zn + 2HCl --> ZnCl2 + H20.5 mole Zn (2 moles HCl/1 mole Zn)= 1 mole HCl================you do not have this much moles HCl0.75 moles HCl (1 mole Zn/2 mole HCl)= 0.375 moles Zn===================you have more moles Zn than thisSo. HCl limits this reaction.
1.88 mol Zn ( 6.022 X10^23/1mol Zn ) = 1.13 X10^24 atoms.
First, write a balanced equation for this reaction. The reactants are HCl and Zn and the products are ZnCl2(aq), and H2(g). For how to write a balanced equation, see the Related Questions to the left. Then, convert the grams of Zn into moles of Zn. To do that, see the Related Questions to the left. Then use stoichiometry to determine how many moles of HCl are necessary to react with that number of moles of Zn. See the Related Questions to the left for how to solve stoichiometry problems. Finally, determine how many milliliters of solution you need to get that many moles of HCl. To do that, use this equation: number of moles = number of liters * molarity
3,80 g Zn have 0,058 moles.
6,022140857.10e23--------------1 mol1,33.10e24----------------------------xx = 1,33.10e24/6,022140857.10e23 = 2,2 moles Zn
I assume you mean this reaction. Zn + 2HCl --> ZnCl2 + H2 2.3 moles zinc (2 moles HCl/1 mole Zn) = 4.6 moles hydrochloric acid needed ========================
0,040 moles Zn equal 2,614 g.
For this you need the atomic mass of Zn. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.671.89 moles Zn × (65.4 grams)) = 10.3 grams Zn
0,356 moles of zinc contain 23,27 g.
The answer is 0,058 moles.
Balanced equation first.Zn + 2HCl --> ZnCl2 + H20.5 mole Zn (2 moles HCl/1 mole Zn)= 1 mole HCl================you do not have this much moles HCl0.75 moles HCl (1 mole Zn/2 mole HCl)= 0.375 moles Zn===================you have more moles Zn than thisSo. HCl limits this reaction.
1.88 mol Zn ( 6.022 X10^23/1mol Zn ) = 1.13 X10^24 atoms.
First, write a balanced equation for this reaction. The reactants are HCl and Zn and the products are ZnCl2(aq), and H2(g). For how to write a balanced equation, see the Related Questions to the left. Then, convert the grams of Zn into moles of Zn. To do that, see the Related Questions to the left. Then use stoichiometry to determine how many moles of HCl are necessary to react with that number of moles of Zn. See the Related Questions to the left for how to solve stoichiometry problems. Finally, determine how many milliliters of solution you need to get that many moles of HCl. To do that, use this equation: number of moles = number of liters * molarity
As shown by the ionic equation of the reaction, Zn (s) + 2 Ag+ (aq) --> 2 Ag (s) + Zn2+ (aq), each mole of zinc produces two moles of silver. Therefore, 1.30 moles of zinc will displace 2.60 moles of silver.
125g = 0.125kg