The equivalent of 125 g zinc is 1, 91 moles.
To find the number of moles in 3.80 g of Zn, you first need to calculate the molar mass of Zn, which is 65.38 g/mol. Then, divide the mass given (3.80 g) by the molar mass to get the number of moles, which is approximately 0.058 moles of Zn.
To find the amount in moles of 3.80g of zinc (Zn), you need to divide the mass by the molar mass of Zn, which is approximately 65.38 g/mol. 3.80g Zn / 65.38 g/mol ≈ 0.058 moles Zn
Calculated by dividing mass (in grams) by atomic mass of Zn: 3.45(g) / 65.38(g/mole) = 0.0528 mole
Using the molar mass of zinc (65.38 g/mol), you can calculate the number of moles in 3.65 g of Zn by dividing the given mass by the molar mass. So, 3.65 g of Zn is equivalent to approximately 0.056 moles of Zn.
As shown by the ionic equation of the reaction, Zn (s) + 2 Ag+ (aq) --> 2 Ag (s) + Zn2+ (aq), each mole of zinc produces two moles of silver. Therefore, 1.30 moles of zinc will displace 2.60 moles of silver.
To find the number of moles in 3.80 g of Zn, you first need to calculate the molar mass of Zn, which is 65.38 g/mol. Then, divide the mass given (3.80 g) by the molar mass to get the number of moles, which is approximately 0.058 moles of Zn.
I assume you mean this reaction. Zn + 2HCl --> ZnCl2 + H2 2.3 moles zinc (2 moles HCl/1 mole Zn) = 4.6 moles hydrochloric acid needed ========================
To find the amount in moles of 3.80g of zinc (Zn), you need to divide the mass by the molar mass of Zn, which is approximately 65.38 g/mol. 3.80g Zn / 65.38 g/mol ≈ 0.058 moles Zn
0,040 moles Zn equal 2,614 g.
For this you need the atomic mass of Zn. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.671.89 moles Zn × (65.4 grams)) = 10.3 grams Zn
0,356 moles of zinc contain 23,27 g.
To find the number of moles, divide the number of atoms by Avogadro's number (6.022 x 10^23 atoms/mol). For 1.33 x 10^24 Zn atoms, we have: 1.33 x 10^24 Zn atoms / 6.022 x 10^23 atoms/mol ≈ 2.21 moles of Zn atoms.
Calculated by dividing mass (in grams) by atomic mass of Zn: 3.45(g) / 65.38(g/mole) = 0.0528 mole
Using the molar mass of zinc (65.38 g/mol), you can calculate the number of moles in 3.65 g of Zn by dividing the given mass by the molar mass. So, 3.65 g of Zn is equivalent to approximately 0.056 moles of Zn.
As shown by the ionic equation of the reaction, Zn (s) + 2 Ag+ (aq) --> 2 Ag (s) + Zn2+ (aq), each mole of zinc produces two moles of silver. Therefore, 1.30 moles of zinc will displace 2.60 moles of silver.
The formula given shows that each formula unit of KCl contains one atom of potassium. Therefore, the number of moles of potassium will be the same as the number of moles of KCl, and its gram formula mass is 74.55. therefore, the number of moles is 125/74.55 or 1.68, to the justified number of significant digits.
To find the number of atoms in 1.88 moles of Zn, you would multiply the number of moles by Avogadro's number, which is 6.022 x 10^23 atoms/mol. Therefore, there are approximately 1.13 x 10^24 atoms in 1.88 moles of Zn.