0,356 moles of zinc contain 23,27 g.
To calculate the number of moles of zinc, use the formula: moles = mass (grams) / molar mass (grams/mol). The molar mass of zinc (Zn) is approximately 65.38 g/mol. Therefore, 125 grams of zinc is equal to 125 g / 65.38 g/mol, which is about 1.91 moles of zinc.
To determine how many grams of zinc chloride (ZnCl₂) are needed to react with 45 grams of aluminum (Al), we first need to look at the balanced chemical equation for the reaction, which is: [ 2Al + 3ZnCl₂ \rightarrow 2AlCl₃ + 3Zn ] From the equation, 2 moles of aluminum react with 3 moles of zinc chloride. The molar mass of aluminum is approximately 27 g/mol, so 45 grams of aluminum corresponds to about 1.67 moles of Al. Thus, we need 2.5 moles of ZnCl₂ (since 1.67 moles Al will require 2.5 moles ZnCl₂). The molar mass of ZnCl₂ is about 136.3 g/mol, so 2.5 moles of ZnCl₂ would weigh approximately 340.75 grams.
You need the molar solution to get the number of moles present in 6.52g of Zinc Sulfate.
To determine the amount of zinc sulfate produced, we first need to look at the balanced chemical reaction between zinc and lead(IV) sulfate. The reaction is: [ \text{Zn} + \text{Pb(SO}_4\text{)}_2 \rightarrow \text{ZnSO}_4 + \text{Pb} ] From the reaction, 1 mole of zinc produces 1 mole of zinc sulfate (ZnSO₄). Therefore, 0.320 moles of zinc will produce 0.320 moles of zinc sulfate. To convert moles to grams, we multiply by the molar mass of zinc sulfate (approximately 161.44 g/mol), resulting in: [ 0.320 , \text{moles} \times 161.44 , \text{g/mol} \approx 51.84 , \text{grams} ] So, 51.84 grams of zinc sulfate would be produced.
Atomic mass from my Periodic Table for Zinc is 65.38. This means 1 mole of naturally occurring zinc has a mass of 65.38 grams. If your zinc sample is pure zinc then: (mass of your sample)/(65.38 grams) = # moles of zinc.
To calculate the number of moles of zinc, use the formula: moles = mass (grams) / molar mass (grams/mol). The molar mass of zinc (Zn) is approximately 65.38 g/mol. Therefore, 125 grams of zinc is equal to 125 g / 65.38 g/mol, which is about 1.91 moles of zinc.
To find the number of moles of zinc in 15 grams, divide the given mass by the molar mass of zinc. The molar mass of zinc is approximately 65.38 g/mol. Therefore, 15 grams of zinc is equal to 0.23 moles of zinc.
For this you need the atomic mass of Zn. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.671.89 moles Zn × (65.4 grams)) = 10.3 grams Zn
Balanced equation first.Zn + 2HCl - ZnCl2 + H2now we find moles HCl by....Molarity = moles of solute/Liters of solution ( 225 ml = 0.225 Liters )0.200 M HCl = X moles/0.225 Liters= 0.045 moles HCl================Now, drive reaction backwards.0.045 moles HCl (1 mole Zn/2 mole HCl)(65.41 grams/1 mole Zn)= 1.47 grams zinc reacted----------------------------------
The equation for the reaction is Zn + 2 HCl -> ZnCl2. The gram atomic masses of zinc and chlorine are 65.39 and 35.453 respectively. Therefore, the number of grams of zinc chloride that can be formed from 7.96 g of zinc is: 7.96{[65.39 + 2(35.453)]/65.39} or about 16.6 g of zinc chloride, to the justified number of significant digits.
1 mol of zinc reacts with 2 moles of chlorine to form zinc chloride. Calculate the number of moles of zinc in 5.00g, then use the mole ratio to determine the moles of chlorine needed. Finally, convert the moles of chlorine to grams.
You need the molar solution to get the number of moles present in 6.52g of Zinc Sulfate.
Atomic mass from my Periodic Table for Zinc is 65.38. This means 1 mole of naturally occurring zinc has a mass of 65.38 grams. If your zinc sample is pure zinc then: (mass of your sample)/(65.38 grams) = # moles of zinc.
For this you need the atomic mass of Zn. Then take the mass in grams and divide it by the atomic number (multiplied by one mole for units to cancel) to find number of moles. Zinc's atomic mass is 65.4 grams.22.5 g Zn / (65.4 grams) = .344 moles Zn
The answer is 2,7 moles.
To find the number of moles of zinc, you can use the formula: moles = mass (g) / molar mass (g/mol). The molar mass of zinc is approximately 65.38 g/mol. Thus, for 125 g of zinc, the calculation would be 125 g / 65.38 g/mol, which equals approximately 1.91 moles of zinc.
To calculate the number of atoms, we need to use Avogadro's number and the molecular weight of zinc. The molar mass of zinc is 65.38 g/mol. First, convert grams to moles: 135 g / 65.38 g/mol = 2.06 moles. Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to find the number of atoms: 2.06 moles * 6.022 x 10^23 atoms/mol = 1.24 x 10^24 atoms of zinc.