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How many grams of aluminum chloride are produced when 54 grams of aluminum react with chlorine gas?
266,86 g aluminium chloride are obtained.
How many grams of aluminum chloride can be made from 67.0 grams of aluminium and excess hydrochloric acid?
To determine the amount of aluminum chloride that can be produced, you need to consider the stoichiometry of the reaction between aluminum and hydrochloric acid. The balanced equation is 2Al + 6HCl → 2AlCl3 + 3H2. From the equation, 2 moles of aluminum produce 2 moles of aluminum chloride. You can use the molar mass of aluminum chloride to convert moles to grams.
How many grams of silver chloride are equal to a mol of silver chloride?
Silver chloride - AgClAg (107.89 grams) + Cl (35.45 grams) = 143.34 grams
How many chloride ions are required to neutralize one aluminum ion?
Aluminum is 3+ and chloride is 1-. So, you need 3 chloride ions to neutralize 1 aluminum ion.
If a solution containing 110.97 g of silver nitrate is allowed to react completely with a solution containing 12.45 g of lithium chloride how many grams of solid precipitate will be formed?
42,09 g silver chloride are obtained.
How many grams of aluminum chloride are produced when 54 grams of aluminum react with chlorine gas?
266,86 g aluminium chloride are obtained.
When 4 moles of aluminum are allowed to react with an excess of chlorine gas Cl2 how many moles of aluminum chloride are produced?
When 4 moles of aluminum react with an excess of chlorine gas, 4 moles of aluminum chloride are produced. This is because the balanced chemical equation for the reaction is: 2Al + 3Cl2 -> 2AlCl3 This means that 2 moles of aluminum react with 3 moles of chlorine gas to produce 2 moles of aluminum chloride, so 4 moles of aluminum will produce 4 moles of aluminum chloride.
How many grams of aluminum chloride can be made from 67.0 grams of aluminium and excess hydrochloric acid?
To determine the amount of aluminum chloride that can be produced, you need to consider the stoichiometry of the reaction between aluminum and hydrochloric acid. The balanced equation is 2Al + 6HCl → 2AlCl3 + 3H2. From the equation, 2 moles of aluminum produce 2 moles of aluminum chloride. You can use the molar mass of aluminum chloride to convert moles to grams.
How many grams of iron iii hydroxide will react with 85g or sodium chloride?
The iron(III) hydroxide is not soluble in water and doesn't react with sodium chloride.
How many grams of aluminum chloride could be produced from 34.0 grams of aluminum and 39.0 grams of chlorine gas?
To find the limiting reactant, we need to calculate the moles of each reactant. Then, use the stoichiometry of the balanced chemical equation to determine which reactant limits the amount of aluminum chloride that can be produced. Finally, calculate the mass of aluminum chloride produced based on the limiting reactant.
How many grams of silver nitrate are needed to react with 50 grams of sodium chloride?
You need 145,337 g silver nitrate.
When 4 moles of aluminum are allowed to react with an excess of chlorine gas CL2 how many moles of aluminum chlorde are produced?
When 4 moles of aluminum react with an excess of chlorine gas (Cl2), 4 moles of aluminum chloride are produced because the balanced chemical equation for this reaction is: 2 Al + 3 Cl2 -> 2 AlCl3 Since the mole ratio between aluminum and aluminum chloride is 2:2, it means that for every 2 moles of aluminum, 2 moles of aluminum chloride are produced.
If 328 grams of aluminum hydroxide react with excess hydrochloric acid how many grams of aluminum chloride can be formed?
Balanced equation first. ( you have been told the limiting reactant. ) Al(OH)3 + 3HCl >> AlCl3 + 3H2O Molar mass Al(OH)3 = 78.004 grams/// Molar mass AlCl3 = 133.33 grams Conversion. 328g Al(OH)3 (1mol Al(OH)3/78.004g)(1 mol AlCl3/1mol Al(OH)3)(133.33g AlCl3/1mol AlCl3) =560.64 grams produced
How many grams of aluminum chloride are produced when 18 grams of aluminum are reacted with an excess of hydrochloride acid?
The empirical formula for aluminum chloride is AlCl3, and its gram formula mass is 133.34. The formula shows that each formula unit contains one aluminum atom, and the the gram atomic mass of aluminum is 26.9815. Therefore, 18(133.34/26.9815) or 89 grams, to the justified number of significant digits, of aluminum chloride will be produced.
How many Al atoms and how many Cl atoms are in aluminum chloride?
The ratio in aluminum chloride is 1:3 aluminum to chloride ( AlCl3 or Al2Cl6 )
How many atoms of chlorine are in aluminum chloride?
There are 3 atoms of chlorine in aluminum chloride (AlCl3).
A sample of 27.0g of aluminum yields 266.7g of aluminum bromide how many grams of bromine react with 15.0g of aluminum?
To find the grams of bromine that react with 15.0g of aluminum, we need to first calculate the molar mass of aluminum and aluminum bromide. Then, find the moles of aluminum reacted using its mass and molar mass. Using the mole ratio from the balanced chemical equation, we can find the moles of bromine that react. Finally, convert the moles of bromine to grams using its molar mass.
