Balanced equation first. ( you have been told the limiting reactant. )
Al(OH)3 + 3HCl >> AlCl3 + 3H2O
Molar mass Al(OH)3 = 78.004 grams/// Molar mass AlCl3 = 133.33 grams
Conversion.
328g Al(OH)3 (1mol Al(OH)3/78.004g)(1 mol AlCl3/1mol Al(OH)3)(133.33g AlCl3/1mol AlCl3) =560.64 grams produced
4 moles
1.26 mol of AlCl3
it forms a white precipitate ; Al(OH)3 and ammonium sulfate with additional excess NH4OH,still white ppt wont dissolve this means Aluminum dont make a complex with ammonia
Four:2 Al + 3 Cl2 --> 2 AlCl3so: 4 Al + 6 Cl2 --> 4 AlCl3
Zinc hydroxide Zn(OH)2 is an inorganic chemical compound. It also occurs naturally as 3 rare minerals: wülfingite (orthorhombic), ashoverite and sweetite (both tetragonal).Like the hydroxides of other metals, such as lead, aluminium, beryllium, tin and chromium, zinc hydroxide (and zinc oxide), is amphoteric. Thus it will dissolve readily in a dilute solution of a strong acid, such as HCl, and also in a solution of an alkali such as sodium hydroxide.It can be prepared by adding sodium hydroxide solution, but not in excess, to a solution of any zinc salt. A white precipitate will be seen: Zn2+ + 2OH- → Zn(OH)2.If excess sodium hydroxide is added, the precipitate of zinc hydroxide will dissolve, forming a colorless solution of zincate ion: Zn(OH)2 + 2OH- → Zn(OH)42-. This property can be used as a test for zinc ions in solution, but it is not exclusive, since aluminum and lead compounds behave in a very similar manner. Unlike the hydroxides of aluminum and lead, zinc hydroxide also dissolves in aqueous ammonia to form a colourless, water-soluble ammine complexThe reason that the zinc hydroxide will dissolve is because the ion is normally surrounded by water ligands; when excess sodium hydroxide is added to the solution the hydroxide ions will reduce the complex to a -2 charge and make it soluble. When excess ammonia is added, it sets up an equilibirum which provides hydroxide ions; the formation of hydroxide ions causes a similar reaction as sodium hydroxide and creates a +2 charged complex with a co-ordination number of 4 with the ammonia ligands - this makes the complex soluble so that it dissolves
One such salt would be aluminum chloride since it is soluble but when reacted with ammonium hydroxide, the insoluble aluminum hydroxide forms a precipitate. Not sure what is meant by "is insoluble in excess", however.
The answer is: approx. 327 g.
0.80
aluminum hydroxide magnesium hydroxide simethicon
10.4g
Calcium chloride (CaCl2) resulted: 2,772 g.
The products are magnesium chloride and water.
4 moles
Most medications include antacids, which are weak bases (e.g. calcium carbonate, aluminum hydroxide, magnesium hydroxide) to neutralize excess stomach acid.
1.26 mol of AlCl3
The empirical formula for aluminum chloride is AlCl3, and its gram formula mass is 133.34. The formula shows that each formula unit contains one aluminum atom, and the the gram atomic mass of aluminum is 26.9815. Therefore, 18(133.34/26.9815) or 89 grams, to the justified number of significant digits, of aluminum chloride will be produced.
To ensure there's enough of it to allow the reaction to go to completion.