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How many grams of aluminum chloride can be made from 67.0 grams of aluminium and excess hydrochloric acid?
To determine the amount of aluminum chloride that can be produced, you need to consider the stoichiometry of the reaction between aluminum and hydrochloric acid. The balanced equation is 2Al + 6HCl → 2AlCl3 + 3H2. From the equation, 2 moles of aluminum produce 2 moles of aluminum chloride. You can use the molar mass of aluminum chloride to convert moles to grams.
How many grams of strontium chloride are produced by the reaction?
The amount of strontium chloride produced in a reaction would depend on the specific reaction involved and the stoichiometry of the reaction. To calculate the grams produced, you would need to know the balanced chemical equation, the amount of the starting materials used, and use stoichiometry to determine the amount of strontium chloride produced.
How many grams of silver chloride can be produced if you start with 4.62 grams of barium chloride 2AgNO3 plus BaCl2 and mdash and gt 2AgCl plus Ba(NO3)?
6,36 g of silver chloride are obtained.
What is the concentration of a solution with a volume of 660 that contains 33.4 grams out aluminum chloride?
The concentration is 50,6 g/L.
How many grams are in strontium chloride?
Well, honey, strontium chloride has a molar mass of about 158.53 grams per mole. So, if you're looking for the amount of grams in a specific quantity of strontium chloride, you'll need to do a little math based on the number of moles you have. But hey, don't stress too much, just grab a calculator and you'll have your answer in no time.
How many grams of aluminum chloride could be produced from 34.0 grams of aluminum and 39.0 grams of chlorine gas?
To find the limiting reactant, we need to calculate the moles of each reactant. Then, use the stoichiometry of the balanced chemical equation to determine which reactant limits the amount of aluminum chloride that can be produced. Finally, calculate the mass of aluminum chloride produced based on the limiting reactant.
What is the maximum mass of aluminum chloride that can be formed when reacting 24.0 of aluminum with 29.0 of chlorine?
36.4 Grams
What is the maximum mass of aluminum chloride that can be formed when reacting 28.0g of aluminum with 33.0g of chlorine?
The formula of aluminium chloride is AlCl3. The atomic weight of aluminium is 27 and that of chlorine is 35.5. That means 35.5*3 grams of chlorine will combine with 27 grams of aluminium. So 33 grams of chlorine will combine with 8.37 grams of aluminium. The addition of both makes it 41.37 grams. In this reaction, the whole chlorine will be utilized and only part of the aluminium.
If 75 grams of sodium reacts with 25 grams of chlorine how many grams of salt will be produced?
75 g sodium chloride contain 29,75 g sodium.
The molar mass of aluminum chloride is grams?
The molar mass of anhydrous aluminum chloride is 133,34 grams.
What is the maximum mass of aluminum chloride that can be formed when reacting 24.0 g of aluminum with 29.0 g of chlorine?
The gram atomic mass of aluminum is 26.9815; the gram atomic mass of chlorine is 35.453; and the formula of aluminum chloride is AlCl3, showing that three atoms of chlorine are required for each atom of aluminum in the compound. Therefore, mass ratio of chlorine to aluminum in the compound is [3 X (35.453])/26.9815 or 3.942. The ratio of reactant chlorine stated to be available to reactant aluminum stated to be available is 29.0/24.0 or 1.20, so that chlorine is clearly the limiting reactant. Therefore, the mass of aluminum in the maximum mass of aluminum chloride that can be made from the reactants stated is 29.0/3.942 or about 7.357 grams, and that added to the stated 29.0 g of chlorine constitutes 36.4 grams total of aluminum chloride, to the justified number of significant digits.
How many grams of aluminum chloride can be made from 67.0 grams of aluminium and excess hydrochloric acid?
To determine the amount of aluminum chloride that can be produced, you need to consider the stoichiometry of the reaction between aluminum and hydrochloric acid. The balanced equation is 2Al + 6HCl → 2AlCl3 + 3H2. From the equation, 2 moles of aluminum produce 2 moles of aluminum chloride. You can use the molar mass of aluminum chloride to convert moles to grams.
How many grams of Chlorine are in 7 grams of Sodium Chloride?
To find the answer, we multiply the 7 grams of NaCl by the ratio of the molar mass of chlorine over the molar mass of sodium chloride. By doing this, we find that there are about 4.25 grams of chlorine in 7 grams of NaCl.
There is 46 grams of sodium and 23 grams of Chlorine How many gram of sodium chloride can be produced?
Balanced equation. 2Na + Cl2 >> 2NaCl 46 grams sodium = 2 mol 23 grams Chlorine = 0.65 mol ( I think Chlorine is limiting ) 0.65 mol Cl (2mol Na/1mol Cl ) = 1.3 mol ( you do not have that; Cl limits ) 0.65 mol Cl (2mol NaCl/1mol Cl2 )(58.44g/1mol NaCl ) = 75.9 grams
How many grams of aluminum chloride could be produced from 35.5g of aluminum and 39.0g of chlorine gas?
The balanced chemical equation for the reaction is: 2Al + 3Cl₂ → 2AlCl₃ Calculate the limiting reactant: Moles of Al: 35.5g / molar mass of Al Moles of Cl₂: 39.0g / molar mass of Cl₂ Determine which reactant gives the lower amount of AlCl₃ produced. Once you know the limiting reactant, use stoichiometry to calculate the grams of AlCl₃ produced.
How many grams of chlorine gas are needed to make 117 grams of sodium chloride?
117 grams of sodium chloride (NaCl) is equivalent to 117 grams of chlorine gas because each molecule of NaCl contains one sodium atom and one chlorine atom.
When 10.0 grams of calcium reacts with 20.0 grams of chlorine gas, how many grams of calcium chloride can be produced Which reactant is in excess and which is the limiting reactant?
The balanced chemical equation for the reaction between calcium and chlorine gas to produce calcium chloride is: Ca + Cl2 -> CaCl2. From this equation, we can see that one mole of calcium reacts with one mole of chlorine gas to produce one mole of calcium chloride. The molar mass of calcium is 40.08 g/mol and the molar mass of chlorine gas is 70.90 g/mol. This means that 10.0 grams of calcium is equivalent to 0.249 moles of calcium and 20.0 grams of chlorine gas is equivalent to 0.282 moles of chlorine gas. Since the ratio of calcium to chlorine gas in the balanced chemical equation is 1:1, this means that 0.249 moles of calcium would react completely with 0.249 moles of chlorine gas, leaving an excess of 0.033 moles (or 2.34 grams) of chlorine gas. The limiting reactant in this reaction is calcium, and the maximum amount of calcium chloride that can be produced is equivalent to the number of moles of the limiting reactant, which is 0.249 moles (or 27.8 grams) of calcium chloride.
