The amount of strontium chloride produced in a reaction would depend on the specific reaction involved and the stoichiometry of the reaction. To calculate the grams produced, you would need to know the balanced chemical equation, the amount of the starting materials used, and use stoichiometry to determine the amount of strontium chloride produced.
Well, honey, strontium chloride has a molar mass of about 158.53 grams per mole. So, if you're looking for the amount of grams in a specific quantity of strontium chloride, you'll need to do a little math based on the number of moles you have. But hey, don't stress too much, just grab a calculator and you'll have your answer in no time.
266,86 g aluminium chloride are obtained.
To determine the amount of aluminum chloride that can be produced, you need to consider the stoichiometry of the reaction between aluminum and hydrochloric acid. The balanced equation is 2Al + 6HCl → 2AlCl3 + 3H2. From the equation, 2 moles of aluminum produce 2 moles of aluminum chloride. You can use the molar mass of aluminum chloride to convert moles to grams.
6,36 g of silver chloride are obtained.
At 10°C, the solubility of strontium bromide (SrBr₂) in water is approximately 3.5 grams per 100 grams of water. This means that you can dissolve about 3.5 grams of strontium bromide in 100 grams of water at this temperature.
5.53 g
Well, honey, strontium chloride has a molar mass of about 158.53 grams per mole. So, if you're looking for the amount of grams in a specific quantity of strontium chloride, you'll need to do a little math based on the number of moles you have. But hey, don't stress too much, just grab a calculator and you'll have your answer in no time.
Lithium chloride is not transformed in calcium chloride.
The reaction between potassium chlorate and oxygen gas generates potassium chloride and oxygen gas. Therefore, the amount of potassium chlorate produced from the reaction is equal to the amount of potassium chlorate that was used, which is 500 grams.
To calculate the mass of silver chloride produced, we need to use the concept of stoichiometry. Firstly, write the balanced chemical equation for the reaction between silver nitrate and sodium chloride. Then, use the molarity of silver nitrate and the stoichiometry of the reaction to find the moles of silver chloride produced. Finally, convert the moles of silver chloride to grams using its molar mass.
266,86 g aluminium chloride are obtained.
It depends on the chemical reaction that is occurring. Can you provide the balanced equation for the reaction so we can calculate the amount of NaCl produced?
To find the limiting reactant, we need to calculate the moles of each reactant. Then, use the stoichiometry of the balanced chemical equation to determine which reactant limits the amount of aluminum chloride that can be produced. Finally, calculate the mass of aluminum chloride produced based on the limiting reactant.
To determine the amount of aluminum chloride that can be produced, you need to consider the stoichiometry of the reaction between aluminum and hydrochloric acid. The balanced equation is 2Al + 6HCl → 2AlCl3 + 3H2. From the equation, 2 moles of aluminum produce 2 moles of aluminum chloride. You can use the molar mass of aluminum chloride to convert moles to grams.
6,36 g of silver chloride are obtained.
20 grams of silver nitrate would produce an equivalent amount of silver chloride if all the silver nitrate is converted. The molar ratio of AgNO3 to AgCl is 1:1, so 20 grams of AgNO3 would produce 20 grams of AgCl.
To find the limiting reactant, we need to determine how many grams of silver chloride can be produced from each reactant and compare the results. Calculate the amount of silver chloride that can be produced from 10.0 g of silver nitrate. Calculate the amount of silver chloride that can be produced from 15.0 g of barium chloride. The reactant that produces the lesser amount of silver chloride will be the limiting reactant.