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Balanced equation.

2Na + Cl2 >> 2NaCl

46 grams sodium = 2 mol

23 grams Chlorine = 0.65 mol ( I think Chlorine is limiting )

0.65 mol Cl (2mol Na/1mol Cl ) = 1.3 mol ( you do not have that; Cl limits )

0.65 mol Cl (2mol NaCl/1mol Cl2 )(58.44g/1mol NaCl ) = 75.9 grams

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How many grams of chlorine gas are needed to make 117 grams of sodium chloride?

117 grams of sodium chloride (NaCl) is equivalent to 117 grams of chlorine gas because each molecule of NaCl contains one sodium atom and one chlorine atom.


A flask is weighed and has a mass of 50.0 grams Then 2.0 grams of sodium metal is added to the flask Chlorine gas is pumped into the flask This allows the sodium metal to react completely with c?

The sodium metal will react with chlorine gas to form sodium chloride. The reaction involves a single displacement reaction where sodium replaces chlorine in its diatomic form to form NaCl. The final mass of the flask will increase by 2.0 grams due to the formation of sodium chloride.


Is there a limit to the amount of sodium chloride that will dissolve in 30 grams of water?

Yes, there is a limit to the amount of sodium chloride that can dissolve in 30 grams of water. This limit is known as the solubility of sodium chloride in water. At room temperature, approximately 36 grams of sodium chloride can dissolve in 100 grams of water.


If 2 moles of sodium carbonate are used in the reaction how many grams of sodium chloride will be formed?

By stoichiometry, 2 moles of sodium carbonate will produce 2 moles of sodium chloride. The molar mass of sodium chloride is approximately 58.44 g/mol, so 2 moles would weigh about 116.88 grams.


How many grams are in 3.80mol of sodium chloride?

To find the number of grams in 3.80 mol of sodium chloride, you need to multiply the number of moles by the molar mass of sodium chloride. The molar mass of sodium chloride (NaCl) is 58.44 g/mol. Therefore, 3.80 mol * 58.44 g/mol = 222.13 grams of sodium chloride.

Related Questions

If 75 grams of sodium reacts with 25 grams of chlorine how many grams of salt will be produced?

75 g sodium chloride contain 29,75 g sodium.


How many grams of Chlorine are in 7 grams of Sodium Chloride?

To find the answer, we multiply the 7 grams of NaCl by the ratio of the molar mass of chlorine over the molar mass of sodium chloride. By doing this, we find that there are about 4.25 grams of chlorine in 7 grams of NaCl.


How many gram of chlorine are need to combined with 23gram of sodium to make 58.5gram of sodium chloride?

You would need 35.5 grams of chlorine to combine with 23 grams of sodium to make 58.5 grams of sodium chloride. This is based on the molar mass of sodium chloride, where one mole of sodium chloride is composed of one mole of sodium (23 grams) and one mole of chlorine (35.5 grams).


How much table salt is produced when you combine sodium with 1.5 grams of chlorine gas?

When sodium reacts with chlorine gas in a 1:1 molar ratio, the resulting compound is table salt (sodium chloride). The molar mass of sodium chloride is approximately 58.5 g/mol. Therefore, when you combine 1.5 grams of chlorine gas with sodium, you would produce approximately 58.5 grams of table salt.


How many grams of chlorine gas are needed to make 117 grams of sodium chloride?

117 grams of sodium chloride (NaCl) is equivalent to 117 grams of chlorine gas because each molecule of NaCl contains one sodium atom and one chlorine atom.


How many grams of sodium metal are needed to make 29.3 grams of sodium chloride?

Since sodium chloride has equal parts of sodium and chlorine by weight, you would need 29.3 grams of sodium to create 29.3 grams of sodium chloride.


How many grams of chlorine to produce 10 grams of table salt?

To produce 10 grams of table salt (sodium chloride), you would need roughly 10 grams of chlorine gas. This is because the balanced chemical equation for the reaction between sodium and chlorine to form sodium chloride (table salt) is 2Na + Cl2 -> 2NaCl.


What mass of sodium chloride is formed if 22.99 grams of sodium combines with 35.54 grams of chlorine?

The molar mass of sodium chloride is 58.44 g/mol. To find the mass of sodium chloride formed, you need to compare the moles of sodium and chlorine to determine the limiting reactant. Calculate moles of sodium and chlorine, determine limiting reactant, and use stoichiometry to find mass of sodium chloride formed.


How many grams of aluminum chloride are produced when 54 grams of aluminum react with chlorine gas?

266,86 g aluminium chloride are obtained.


A flask is weighed and has a mass of 50.0 grams Then 2.0 grams of sodium metal is added to the flask Chlorine gas is pumped into the flask This allows the sodium metal to react completely with c?

The sodium metal will react with chlorine gas to form sodium chloride. The reaction involves a single displacement reaction where sodium replaces chlorine in its diatomic form to form NaCl. The final mass of the flask will increase by 2.0 grams due to the formation of sodium chloride.


In a reaction between sodium and chlorine 10 grams of sodium is needed to prepare 35 grams of sodium chloride How many grams of chlorine is needed for this reaction?

Since the reaction involves the formation of sodium chloride (NaCl), the molar ratio of sodium to chlorine is 1:1. Therefore, if 10 grams of sodium reacts to form 35 grams of NaCl, then 35 grams of chlorine is also needed for this reaction.


How many grams of sodium chloride would be made if 46 grams of sodium completely reacted with 70 grams of chlorde?

The atomic or ionic mass of sodium is 22.99, and the atomic or ionic mass of chlorine is 35.45. A formula unit of sodium chloride contain one ion of each. Therefore, the mass ratio between sodium and chlorine in sodium chloride is 0.649. The mass ratio between 46 and 70 is 0.657. Therefore, chloride is the limiting reactant in this pair. The mass ratio of chloride to sodium chloride is 35.54/(22.99 + 35.54) or 0.607. Therefore, the mass of sodium chloride formed will be 70/(0.607) or 115 gm, where the depressed last digit indicates that it may not be accurate to + 1. (The limiting datum, 70, has only two significant digits.)