Balanced equation.
2Na + Cl2 >> 2NaCl
46 grams sodium = 2 mol
23 grams Chlorine = 0.65 mol ( I think Chlorine is limiting )
0.65 mol Cl (2mol Na/1mol Cl ) = 1.3 mol ( you do not have that; Cl limits )
0.65 mol Cl (2mol NaCl/1mol Cl2 )(58.44g/1mol NaCl ) = 75.9 grams
117 grams of sodium chloride (NaCl) is equivalent to 117 grams of chlorine gas because each molecule of NaCl contains one sodium atom and one chlorine atom.
The sodium metal will react with chlorine gas to form sodium chloride. The reaction involves a single displacement reaction where sodium replaces chlorine in its diatomic form to form NaCl. The final mass of the flask will increase by 2.0 grams due to the formation of sodium chloride.
Yes, there is a limit to the amount of sodium chloride that can dissolve in 30 grams of water. This limit is known as the solubility of sodium chloride in water. At room temperature, approximately 36 grams of sodium chloride can dissolve in 100 grams of water.
By stoichiometry, 2 moles of sodium carbonate will produce 2 moles of sodium chloride. The molar mass of sodium chloride is approximately 58.44 g/mol, so 2 moles would weigh about 116.88 grams.
To find the number of grams in 3.80 mol of sodium chloride, you need to multiply the number of moles by the molar mass of sodium chloride. The molar mass of sodium chloride (NaCl) is 58.44 g/mol. Therefore, 3.80 mol * 58.44 g/mol = 222.13 grams of sodium chloride.
75 g sodium chloride contain 29,75 g sodium.
To find the answer, we multiply the 7 grams of NaCl by the ratio of the molar mass of chlorine over the molar mass of sodium chloride. By doing this, we find that there are about 4.25 grams of chlorine in 7 grams of NaCl.
You would need 35.5 grams of chlorine to combine with 23 grams of sodium to make 58.5 grams of sodium chloride. This is based on the molar mass of sodium chloride, where one mole of sodium chloride is composed of one mole of sodium (23 grams) and one mole of chlorine (35.5 grams).
When sodium reacts with chlorine gas in a 1:1 molar ratio, the resulting compound is table salt (sodium chloride). The molar mass of sodium chloride is approximately 58.5 g/mol. Therefore, when you combine 1.5 grams of chlorine gas with sodium, you would produce approximately 58.5 grams of table salt.
117 grams of sodium chloride (NaCl) is equivalent to 117 grams of chlorine gas because each molecule of NaCl contains one sodium atom and one chlorine atom.
Since sodium chloride has equal parts of sodium and chlorine by weight, you would need 29.3 grams of sodium to create 29.3 grams of sodium chloride.
To produce 10 grams of table salt (sodium chloride), you would need roughly 10 grams of chlorine gas. This is because the balanced chemical equation for the reaction between sodium and chlorine to form sodium chloride (table salt) is 2Na + Cl2 -> 2NaCl.
The molar mass of sodium chloride is 58.44 g/mol. To find the mass of sodium chloride formed, you need to compare the moles of sodium and chlorine to determine the limiting reactant. Calculate moles of sodium and chlorine, determine limiting reactant, and use stoichiometry to find mass of sodium chloride formed.
266,86 g aluminium chloride are obtained.
The sodium metal will react with chlorine gas to form sodium chloride. The reaction involves a single displacement reaction where sodium replaces chlorine in its diatomic form to form NaCl. The final mass of the flask will increase by 2.0 grams due to the formation of sodium chloride.
Since the reaction involves the formation of sodium chloride (NaCl), the molar ratio of sodium to chlorine is 1:1. Therefore, if 10 grams of sodium reacts to form 35 grams of NaCl, then 35 grams of chlorine is also needed for this reaction.
The atomic or ionic mass of sodium is 22.99, and the atomic or ionic mass of chlorine is 35.45. A formula unit of sodium chloride contain one ion of each. Therefore, the mass ratio between sodium and chlorine in sodium chloride is 0.649. The mass ratio between 46 and 70 is 0.657. Therefore, chloride is the limiting reactant in this pair. The mass ratio of chloride to sodium chloride is 35.54/(22.99 + 35.54) or 0.607. Therefore, the mass of sodium chloride formed will be 70/(0.607) or 115 gm, where the depressed last digit indicates that it may not be accurate to + 1. (The limiting datum, 70, has only two significant digits.)