To find the answer, we multiply the 7 grams of NaCl by the ratio of the molar mass of chlorine over the molar mass of sodium chloride. By doing this, we find that there are about 4.25 grams of chlorine in 7 grams of NaCl.
You would need 35.5 grams of chlorine to combine with 23 grams of sodium to make 58.5 grams of sodium chloride. This is based on the molar mass of sodium chloride, where one mole of sodium chloride is composed of one mole of sodium (23 grams) and one mole of chlorine (35.5 grams).
Since sodium chloride has equal parts of sodium and chlorine by weight, you would need 29.3 grams of sodium to create 29.3 grams of sodium chloride.
To produce 10 grams of table salt (sodium chloride), you would need roughly 10 grams of chlorine gas. This is because the balanced chemical equation for the reaction between sodium and chlorine to form sodium chloride (table salt) is 2Na + Cl2 -> 2NaCl.
Since the reaction involves the formation of sodium chloride (NaCl), the molar ratio of sodium to chlorine is 1:1. Therefore, if 10 grams of sodium reacts to form 35 grams of NaCl, then 35 grams of chlorine is also needed for this reaction.
Approximately 39 grams of sodium chloride can be dissolved in 100 grams of water at 95 degrees Celsius.
117 grams of sodium chloride (NaCl) is equivalent to 117 grams of chlorine gas because each molecule of NaCl contains one sodium atom and one chlorine atom.
You would need 35.5 grams of chlorine to combine with 23 grams of sodium to make 58.5 grams of sodium chloride. This is based on the molar mass of sodium chloride, where one mole of sodium chloride is composed of one mole of sodium (23 grams) and one mole of chlorine (35.5 grams).
75 g sodium chloride contain 29,75 g sodium.
Since sodium chloride has equal parts of sodium and chlorine by weight, you would need 29.3 grams of sodium to create 29.3 grams of sodium chloride.
To produce 10 grams of table salt (sodium chloride), you would need roughly 10 grams of chlorine gas. This is because the balanced chemical equation for the reaction between sodium and chlorine to form sodium chloride (table salt) is 2Na + Cl2 -> 2NaCl.
Balanced equation. 2Na + Cl2 >> 2NaCl 46 grams sodium = 2 mol 23 grams Chlorine = 0.65 mol ( I think Chlorine is limiting ) 0.65 mol Cl (2mol Na/1mol Cl ) = 1.3 mol ( you do not have that; Cl limits ) 0.65 mol Cl (2mol NaCl/1mol Cl2 )(58.44g/1mol NaCl ) = 75.9 grams
Sodium chloride (NaCl) contain two atoms: 1 sodium and 1 chlorine.
Since the reaction involves the formation of sodium chloride (NaCl), the molar ratio of sodium to chlorine is 1:1. Therefore, if 10 grams of sodium reacts to form 35 grams of NaCl, then 35 grams of chlorine is also needed for this reaction.
Sodium chloride (NaCl) formula unit has one chlorine atom.
It depends on the concentration of sodium chloride.
23.3772 grams are there in four tenths moles of sodium chloride
Sodium chloride is composed of two elements, sodium (Na) and chlorine (Cl), which join together to form the compound. Sodium contributes one electron to chlorine for bonding, creating the stable ionic compound sodium chloride.