Silver chloride - AgCl
Ag (107.89 grams) + Cl (35.45 grams) = 143.34 grams
6,36 g of silver chloride are obtained.
9.11 g
One troy ounce of silver = 0.91146 gramsThere are thirty one grams in a Troyounce.
42,09 g silver chloride are obtained.
A thousand times as many grams as there are kilograms.
The answer is 14,35 g AgCl.
6,36 g of silver chloride are obtained.
To find the limiting reactant, we need to determine how many grams of silver chloride can be produced from each reactant and compare the results. Calculate the amount of silver chloride that can be produced from 10.0 g of silver nitrate. Calculate the amount of silver chloride that can be produced from 15.0 g of barium chloride. The reactant that produces the lesser amount of silver chloride will be the limiting reactant.
You need 145,337 g silver nitrate.
9.11 g
20 grams of silver nitrate would produce an equivalent amount of silver chloride if all the silver nitrate is converted. The molar ratio of AgNO3 to AgCl is 1:1, so 20 grams of AgNO3 would produce 20 grams of AgCl.
When silver nitrate reacts with sodium chloride, silver chloride is formed according to the equation: AgNO3 + NaCl -> AgCl + NaNO3. The molar ratio of silver nitrate to silver chloride is 1:1. Therefore, 100 g of silver nitrate will produce 143.32 g of silver chloride.
One gram is equal to .035274 ounces. After conversion then, in one ounce of silver there are 28.3495 grams of silver.
One troy ounce of silver = 0.91146 gramsThere are thirty one grams in a Troyounce.
The formula of chromium chloride is CrCl3 and the formula for silver chloride is AgCl. The relevant formula unit masses are 158.36 for chromium (III) chloride and 143.32 for silver chloride. The gram atomic masses of chlorine, chromium, and silver are 35.453, 51.996, and 107.866 respectively. Therefore, the mass fraction of chloride in chromium (III) chloride is [3(35.453)/158.36] or 0.671628 and the mass fraction of chloride in silver chloride is 35.453/143.32 or 0.24737. Therefore, to form 75.0 g of silver chloride, (0.24737)(75.0) or 18.55 g of chloride is needed, and this amount of chloride is contained in 18.55/0.6716 or 27.6 g of chromium (III) chloride, to the justified number of significant digits.
Since sodium chloride has equal parts of sodium and chlorine by weight, you would need 29.3 grams of sodium to create 29.3 grams of sodium chloride.
That is just less than 1/2 teaspoon.