Atomic Mass from my Periodic Table for Zinc is 65.38. This means 1 mole of naturally occurring zinc has a mass of 65.38 grams.
If your zinc sample is pure zinc then:
(mass of your sample)/(65.38 grams) = # moles of zinc.
To determine the moles of H₂ produced from the reaction between magnesium (Mg) and sulfuric acid (H₂SO₄), we start with the balanced chemical equation: [ \text{Mg} + \text{H}_2\text{SO}_4 \rightarrow \text{MgSO}_4 + \text{H}_2 ] From the equation, 1 mole of Mg produces 1 mole of H₂. The molar mass of Mg is approximately 24.31 g/mol. Given 230 mg of Mg (or 0.230 g), the moles of Mg are calculated as follows: [ \text{Moles of Mg} = \frac{0.230 , \text{g}}{24.31 , \text{g/mol}} \approx 0.00946 , \text{moles} ] Thus, 0.00946 moles of Mg will produce approximately 0.00946 moles of H₂.
For this you need the atomic (molecular) mass of NaNO3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. NaNO3=85.0 grams60.1 grams NaNO3 / (85.0 grams) = .707 moles NaNO3
There are 230 pounds in 230 pounds. One pound is equivalent to 16 ounces. Therefore, 230 pounds is equivalent to 230 x 16 = 3,680 ounces.
Uranium-230 is a radioactive isotope of uranium with 142 neutrons.
230 centimeters is 7.55 feet.
To calculate the number of moles of HCl, you need to use the formula: moles = Molarity (M) x Volume (L) Convert 230 cm^3 to liters: 230 cm^3 ÷ 1000 = 0.23 L Now, plug in the values: moles = 2M x 0.23 L = 0.46 moles of HCl in 230 cm^3 of 2M hydrochloric acid.
To find the molarity, first calculate the number of moles of LiCl in 230 mL of water. Then, divide the moles of LiCl by the volume of water in liters (230 mL = 0.23 L) to get the molarity. In this case, 2.60 moles of LiCl in 0.23 L of water would result in a molarity of 11.30 mol/L.
To determine the moles of H₂ produced from the reaction between magnesium (Mg) and sulfuric acid (H₂SO₄), we start with the balanced chemical equation: [ \text{Mg} + \text{H}_2\text{SO}_4 \rightarrow \text{MgSO}_4 + \text{H}_2 ] From the equation, 1 mole of Mg produces 1 mole of H₂. The molar mass of Mg is approximately 24.31 g/mol. Given 230 mg of Mg (or 0.230 g), the moles of Mg are calculated as follows: [ \text{Moles of Mg} = \frac{0.230 , \text{g}}{24.31 , \text{g/mol}} \approx 0.00946 , \text{moles} ] Thus, 0.00946 moles of Mg will produce approximately 0.00946 moles of H₂.
2H2 + O2 --> 2H2OAs you can see by the balanced reaction, for every 1 mole of oxygen used, 2 moles of water are formed. Also notice that for every 1 mole of oxygen used, you need 2 moles of hydrogen to produce the 2 moles of water. So in your case 110 moles of oxygen would produce 220 moles of water & would also require 220 moles of hydrogen (which you have in excess since you have 230 moles of hydrogen). So 220 moles of water are the most that can be formed.
one cell is produced from one primary oocyte.
230
For this you need the atomic (molecular) mass of NaNO3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. NaNO3=85.0 grams60.1 grams NaNO3 / (85.0 grams) = .707 moles NaNO3
230
1 mole Na = 22.989770g 10 moles Na = 10 x 22.989770g = 229.89770g
230 meters = 251.53 yards
230 kilometers = 230,000 meters
230 yards = 0.130681818 miles