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If you have 125 grams of zinc how many moles of zinc do you have?
To calculate the number of moles of zinc, use the formula: moles = mass (grams) / molar mass (grams/mol). The molar mass of zinc (Zn) is approximately 65.38 g/mol. Therefore, 125 grams of zinc is equal to 125 g / 65.38 g/mol, which is about 1.91 moles of zinc.
How many grams of Zn are in 0.356 moles of zinc?
0,356 moles of zinc contain 23,27 g.
How many moles of ZnCl2 will be produced from 23.0 g of Zn?
Atomic mass from my Periodic Table for Zinc is 65.38. This means 1 mole of naturally occurring zinc has a mass of 65.38 grams. If your zinc sample is pure zinc then: (mass of your sample)/(65.38 grams) = # moles of zinc.
How do you calculate the mass of 4.87 and times 1025 atoms of Zn?
To calculate the mass of 4.87 x 10²⁵ atoms of zinc (Zn), first determine the number of moles of zinc using Avogadro's number (6.022 x 10²³ atoms/mol). Divide the total number of atoms by Avogadro's number: 4.87 x 10²⁵ atoms ÷ 6.022 x 10²³ atoms/mol ≈ 8.09 moles. Then, multiply the number of moles by the molar mass of zinc (approximately 65.38 g/mol) to find the mass: 8.09 moles x 65.38 g/mol ≈ 528.6 grams.
How many atoms are in 7.1 mol Zn?
From my understanding as there is only one mole of zinc which means the mass is 65.4 . Then to get the number of particles the answer is simply 1(the number of moles) x 6.02 x 10 ^ 23. is this correct this is not the answer just a further question ...
How many grams are in 671.89 moles of zinc?
For this you need the atomic mass of Zn. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.671.89 moles Zn × (65.4 grams)) = 10.3 grams Zn
What is the amount in moles of 3.45 g Zn?
Calculated by dividing mass (in grams) by atomic mass of Zn: 3.45(g) / 65.38(g/mole) = 0.0528 mole
How many moles are in 22.5 grams of zinc?
For this you need the atomic mass of Zn. Then take the mass in grams and divide it by the atomic number (multiplied by one mole for units to cancel) to find number of moles. Zinc's atomic mass is 65.4 grams.22.5 g Zn / (65.4 grams) = .344 moles Zn
How many moles does 3.80 g Zn have?
To find the number of moles in 3.80 g of Zn, you first need to calculate the molar mass of Zn, which is 65.38 g/mol. Then, divide the mass given (3.80 g) by the molar mass to get the number of moles, which is approximately 0.058 moles of Zn.
What is the amount in moles of 3.80g Zn?
To find the amount in moles of 3.80g of zinc (Zn), you need to divide the mass by the molar mass of Zn, which is approximately 65.38 g/mol. 3.80g Zn / 65.38 g/mol ≈ 0.058 moles Zn
If you have 125 grams of zinc how many moles of zinc do you have?
To calculate the number of moles of zinc, use the formula: moles = mass (grams) / molar mass (grams/mol). The molar mass of zinc (Zn) is approximately 65.38 g/mol. Therefore, 125 grams of zinc is equal to 125 g / 65.38 g/mol, which is about 1.91 moles of zinc.
How many moles are in 3.60 g Zn?
To find the number of moles in 3.60 g Zn, you need to divide the mass by the molar mass of Zn. The molar mass of Zn is approximately 65.38 g/mol. So, 3.60 g Zn divided by 65.38 g/mol is equal to approximately 0.055 moles of Zn.
When zinc reacts wiht sulfuirc acid what mass of hydrogen is produced from 31.8g of zinc?
To calculate the mass of hydrogen produced when 31.8g of zinc reacts with sulfuric acid, you need to first balance the chemical equation. The balanced equation is: Zn + H2SO4 → ZnSO4 + H2. Then, use the molar ratio from the balanced equation to convert the mass of zinc to moles, and then to moles of hydrogen. Finally, convert moles of hydrogen to mass using the molar mass of hydrogen.
How many moles are in 125g of Zn?
The equivalent of 125 g zinc is 1, 91 moles.
How many grams of ZnCl2 are formed from150 g of Zn and 73 g of HCl?
To determine the amount of ZnCl2 formed, we first need to find the limiting reactant. Zn is the limiting reactant in this case. The balanced chemical equation is: Zn + 2HCl -> ZnCl2 + H2. Using the given mass of Zn, calculate the moles of Zn, then use the mole ratio from the balanced equation to find the moles of ZnCl2 formed. Finally, convert the moles of ZnCl2 to grams.
How many moles of ZnCl2 will be produced from 28g of Zn assuming CuCl2 is available in excess?
Ok, so we have... Zn + CuCl2 -> ZnCL2 + Cu And we are given that we have 28g of Zn (Zinc). But the question calls for moles of ZnCl2. So, the first step is to convert grams to moles of Zn. We will need to find the AMU (Atomic Mass Units) that a Zn atom's mass. A Zn atom has a mass of 63.546 AMU. Now, we take the given mass and divide it by the mass of the atom to get the moles of reactant we have. 28g/63.546AMU≈ .4406257moles If your teacher/ professor cares about sig figs, then it's .44 because you only have two sig figs from the given from the given mass of Zn (28g). Now, the easy part. What is the ratio of Zn atoms on the reactant side to Zn atoms on the product side? 1:1 And since we have excess CuCl2 Nothing else limits the reaction. So, .44 (or how ever far your teacher wants you to round) moles of Zn reactants in a ideal environment (you will learn later that no reaction is 100% and that there are reactants always left over and how to solve for that) produces .44 moles of ZnCl2.
How many grams of Zn are in 0.356 moles of zinc?
0,356 moles of zinc contain 23,27 g.
