From my understanding as there is only one mole of zinc which means the mass is 65.4 . Then to get the number of particles the answer is simply 1(the number of moles) x 6.02 x 10 ^ 23.
is this correct this is not the answer just a further question ...
To calculate the number of atoms, we need to use Avogadro's number and the molecular weight of zinc. The molar mass of zinc is 65.38 g/mol. First, convert grams to moles: 135 g / 65.38 g/mol = 2.06 moles. Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to find the number of atoms: 2.06 moles * 6.022 x 10^23 atoms/mol = 1.24 x 10^24 atoms of zinc.
To find the number of atoms in 12g of zinc, you would first determine the molar mass of zinc (65.38 g/mol), then calculate the number of moles in 12g (12g / 65.38 g/mol). Finally, you would convert moles to atoms using Avogadro's number (6.022 x 10^23 atoms/mol) to get the number of atoms.
Zinc bicarbonate, with the chemical formula Zn(HCO₃)₂, contains a total of 9 atoms. This includes 1 zinc atom (Zn), 2 carbon atoms (C), and 6 hydrogen atoms (H), along with 6 oxygen atoms (O) from the two bicarbonate ions. Therefore, the breakdown is 1 Zn + 2 C + 6 H + 6 O = 15 atoms.
The molecular mass of Zinc fluoride (ZnF2) is calculated by adding the atomic masses of zinc (Zn) and two fluorine (F) atoms. The atomic mass of zinc is approximately 65.38 g/mol, and the atomic mass of fluorine is about 18.99 g/mol. Therefore, the molecular mass of ZnF2 is approximately 102.36 g/mol.
A lot of that hydrochloric acrid is excess and some grams will not react, I think. Balanced equation first. Zn + 2HCl -> ZnCl2 + H2 Check to make sure of limiting reactant; I suspect zinc. 1.80 moles Zn (2 mole HCl/1 mole Zn) = 3.60 moles HCl You have a lot more than that, Zn limits and will drive the reaction 1.80 moles Zn (2 moles HCl/1 mole Zn)(36.458 grams/1 mole HCl) = 131 grams of hydrochloric acid reacted with that Zinc amount ----------------------------------------------------------------------------------
To determine the number of atoms in 3.29 mol of Zn, you would use Avogadro's number, which is 6.022 x 10^23 atoms/mol. Multiply the number of moles (3.29 mol) by Avogadro's number to find the number of atoms. The calculation would be: 3.29 mol Zn x 6.022 x 10^23 atoms/mol = 1.98 x 10^24 atoms of Zn.
To find the number of moles, divide the number of atoms by Avogadro's number (6.022 x 10^23 atoms/mol). For 1.33 x 10^24 Zn atoms, we have: 1.33 x 10^24 Zn atoms / 6.022 x 10^23 atoms/mol ≈ 2.21 moles of Zn atoms.
Molar mass of Zinc = 65.4 g mol-1 No. of moles of 20.0 g of Zinc = 20.0 / 65.4 = 0.305810397 mol No. of atoms = 0.305810397 L (where L is the Avogadro constant) = 1.8416 x 1023
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6,78.1022 molecules of glucose 2,14388229924.1024 iron atoms 1,25.1025 zinc atoms
To find the number of atoms in 1.88 moles of Zn, you would multiply the number of moles by Avogadro's number, which is 6.022 x 10^23 atoms/mol. Therefore, there are approximately 1.13 x 10^24 atoms in 1.88 moles of Zn.
There is 1 zinc (Zn) atom in Zn(ClO3)2.
There are 6 oxygen atoms in Zn(ClO3)2.
To calculate the number of atoms, we need to use Avogadro's number and the molecular weight of zinc. The molar mass of zinc is 65.38 g/mol. First, convert grams to moles: 135 g / 65.38 g/mol = 2.06 moles. Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to find the number of atoms: 2.06 moles * 6.022 x 10^23 atoms/mol = 1.24 x 10^24 atoms of zinc.
There are : 1 zinc atom 2 chlorine atoms 6 oxygen atoms in this zinc chlorate molecule.
3 moles of Zn is equal to 18.09x1023 atoms. I used Avogadro's Number : 6.03x1023 particles/mol This number is the number of atoms or molecules in a mol of any substance. 3 moles X 6.03x1023 particles/mol = 18.09x1023 atoms
To find the number of atoms in 12g of zinc, you would first determine the molar mass of zinc (65.38 g/mol), then calculate the number of moles in 12g (12g / 65.38 g/mol). Finally, you would convert moles to atoms using Avogadro's number (6.022 x 10^23 atoms/mol) to get the number of atoms.