1.88 mol Zn ( 6.022 X10^23/1mol Zn ) = 1.13 X10^24 atoms.
8
To determine the number of atoms in 3.29 mol of Zn, you would use Avogadro's number, which is 6.022 x 10^23 atoms/mol. Multiply the number of moles (3.29 mol) by Avogadro's number to find the number of atoms. The calculation would be: 3.29 mol Zn x 6.022 x 10^23 atoms/mol = 1.98 x 10^24 atoms of Zn.
Molar mass of Zinc = 65.4 g mol-1 No. of moles of 20.0 g of Zinc = 20.0 / 65.4 = 0.305810397 mol No. of atoms = 0.305810397 L (where L is the Avogadro constant) = 1.8416 x 1023
To find the number of moles in 3.80 g of Zn, you first need to calculate the molar mass of Zn, which is 65.38 g/mol. Then, divide the mass given (3.80 g) by the molar mass to get the number of moles, which is approximately 0.058 moles of Zn.
There are : 1 zinc atom 2 chlorine atoms 6 oxygen atoms in this zinc chlorate molecule.
To find the number of moles, divide the number of atoms by Avogadro's number (6.022 x 10^23 atoms/mol). For 1.33 x 10^24 Zn atoms, we have: 1.33 x 10^24 Zn atoms / 6.022 x 10^23 atoms/mol ≈ 2.21 moles of Zn atoms.
8
To determine the number of atoms in 3.29 mol of Zn, you would use Avogadro's number, which is 6.022 x 10^23 atoms/mol. Multiply the number of moles (3.29 mol) by Avogadro's number to find the number of atoms. The calculation would be: 3.29 mol Zn x 6.022 x 10^23 atoms/mol = 1.98 x 10^24 atoms of Zn.
Molar mass of Zinc = 65.4 g mol-1 No. of moles of 20.0 g of Zinc = 20.0 / 65.4 = 0.305810397 mol No. of atoms = 0.305810397 L (where L is the Avogadro constant) = 1.8416 x 1023
To find the number of moles in 3.80 g of Zn, you first need to calculate the molar mass of Zn, which is 65.38 g/mol. Then, divide the mass given (3.80 g) by the molar mass to get the number of moles, which is approximately 0.058 moles of Zn.
There are : 1 zinc atom 2 chlorine atoms 6 oxygen atoms in this zinc chlorate molecule.
To find the number of atoms in 12g of zinc, you would first determine the molar mass of zinc (65.38 g/mol), then calculate the number of moles in 12g (12g / 65.38 g/mol). Finally, you would convert moles to atoms using Avogadro's number (6.022 x 10^23 atoms/mol) to get the number of atoms.
15.0553*1023 Zn atomsBy definition of the 'mole' there are ALWAYS 6.02214*1023 particles (of any kind) in ONE mole of that matter. (This BIG number is called the Avogadro number or constant)So this is true for atoms Zn in 1 mole pure zinc, for H2O molecules in 1 mole water, even for sand particles in 1 mole sand (but there is not so much sand in a desert)
3 moles of Zn is equal to 18.09x1023 atoms. I used Avogadro's Number : 6.03x1023 particles/mol This number is the number of atoms or molecules in a mol of any substance. 3 moles X 6.03x1023 particles/mol = 18.09x1023 atoms
For this you need the atomic mass of Zn. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.671.89 moles Zn × (65.4 grams)) = 10.3 grams Zn
To calculate the number of atoms, we need to use Avogadro's number and the molecular weight of zinc. The molar mass of zinc is 65.38 g/mol. First, convert grams to moles: 135 g / 65.38 g/mol = 2.06 moles. Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to find the number of atoms: 2.06 moles * 6.022 x 10^23 atoms/mol = 1.24 x 10^24 atoms of zinc.
The equivalent of 125 g zinc is 1, 91 moles.