How many atoms are in .750 moles of zinc?

Answer 1

15.0553*1023 Zn atoms

By definition of the 'mole' there are ALWAYS 6.02214*1023 particles (of any kind) in ONE mole of that matter. (This BIG number is called the Avogadro number or constant)

So this is true for atoms Zn in 1 mole pure zinc, for H2O molecules in 1 mole water, even for sand particles in 1 mole sand (but there is not so much sand in a desert)

Answer 2

For this problem, the Atomic Mass is not required. Take the mass in moles and multiply it by Avogadro's constant, 6.02 × 1023. Divide by one mole for the units to cancel.

2.95 moles H2 × (6.02 × 1023 atoms) = 1.78 × 1024 atoms

Answer 3

2.50 mole Zn (6.022 X 10^23/1 mole Zn)

= 1.51 X 10^24 atoms in 2.50 moles of zinc

Answer 4

This is 2.50 times Avogadro's number, or 1.51 X 1024 atoms, to the justified number of significant digits.

Answer 5

0,750 moles of zinc contain 4,51660564275.1023 atoms.

Answer 6

1.5 x 10^24