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To calculate the molarity (M) of the NaCl solution, first find the number of moles of NaCl. The molar mass of NaCl is approximately 58.44 g/mol, so 21.04 g of NaCl is about 0.360 moles (21.04 g ÷ 58.44 g/mol). Molarity is defined as moles of solute per liter of solution; therefore, for 750 ml (0.750 L), the molarity is 0.360 moles ÷ 0.750 L = 0.480 M. Thus, the molarity of the NaCl solution is 0.480 M.

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What is the molarity of 750 mL of NaCl solution that contains 21.04 g of NaCl?

To calculate the molarity of the NaCl solution, first convert the mass of NaCl to moles using its molar mass. The molar mass of NaCl is 58.44 g/mol. Then, divide the moles of NaCl by the volume of the solution in liters (750 mL = 0.75 L) to get the molarity. In this case, the molarity of the NaCl solution is 1.5 M.


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The molarity of the solution is calculated by dividing the moles of solute (0.250 mol NaCl) by the liters of solution (2.25 L). Molarity = moles of solute / liters of solution Molarity = 0.250 mol / 2.25 L = 0.111 M


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Molarity = moles of solute/Liters of solution Molarity = 6 Moles NaCl/2 Liters = 3 M NaCl ========


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To calculate the molarity of a 5% NaCl solution, you need to know the density of the solution. Once you have the density, you can convert the percentage to grams per liter. Then, using the molar mass of NaCl (58.44 g/mol), you can calculate the molarity using the formula Molarity = (mass of solute in g) / (molar mass of solute in g/mol) / (volume of solution in L).


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Need moles NaCl first. 17.52 grams NaCl (1 mole NaCl/58.44 grams) = 0.29979 moles NaCl =====================Now. Molarity = moles of solute/Liters of solution ( 2000 ml = 2 Liters ) Molarity = 0.29979 mole NaCl/2 Liters = 0.1499 M NaCl ----------------------


What volume (in milliliters) of a 0.150 M salt water solution contains 0.500 g of NaCl?

To find the volume of the solution containing 0.500 g of NaCl, first, calculate the moles of NaCl using its molar mass (58.44 g/mol). Then use the molarity formula (Molarity = moles/volume) to find the volume. The volume of a 0.150 M solution that contains 0.500 g of NaCl would be approximately 8.5 ml.


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After transferring 50 grams of the 1.7 M NaCl solution to a new beaker, the final amount of NaCl in the original beaker will be 50 grams. To find the new molarity, you would first calculate the new moles of NaCl in the beaker, then divide by the total volume of the solution in liters. The molarity will be reduced in the original beaker due to the dilution from transferring a portion of the solution.


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The concentration of NaCl in a solution that contains 0.9 NaCl is 0.9 grams of NaCl per 100 grams of solution.


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To find the volume of the solution, first calculate the moles of NaCl in 0.500 g using its molar mass. Then, use the concentration to determine the volume using the formula: moles = molarity x volume. Rearrange the formula to solve for volume, which would be moles / molarity. Substituting the moles of NaCl and the concentration into the formula will give you the volume of the solution.


Equal moles of H2O and NaCl are present in a solution Hence molarity of NaCl is?

I suppose that this situation is not possible.