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Molarity = moles of solute/Liters of solution

Molarity = 6 Moles NaCl/2 Liters

= 3 M NaCl

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What is the molarity of a solution consisting of 0.250 mol NaCl dissolved in 2.25 L of solution?

The molarity of the solution is calculated by dividing the moles of solute (0.250 mol NaCl) by the liters of solution (2.25 L). Molarity = moles of solute / liters of solution Molarity = 0.250 mol / 2.25 L = 0.111 M


What molarity of 6 moles of nacl dissolve in 2 l of water?

This molarity is 3 M.


How do you calculate the molarity of the solution of 17.52 grams of Na Cl in a total volume of 2000 ml of solution?

Need moles NaCl first. 17.52 grams NaCl (1 mole NaCl/58.44 grams) = 0.29979 moles NaCl =====================Now. Molarity = moles of solute/Liters of solution ( 2000 ml = 2 Liters ) Molarity = 0.29979 mole NaCl/2 Liters = 0.1499 M NaCl ----------------------


What is the molarity of 6 moles of NaCl dissolves in 2 L of water?

Molarity is defined as moles solute/liter of solution6 moles/2 liters solution = 3 molar NOTE: This assumes no volume change and 2L is the final volume of solution.


What is the concentration M of a NaCl solution prepared by dissolving 3.8 g of NaCl in sufficient water to give 245 mL of solution?

Get moles NaCl and change 245 ml to 0.245 Liters. 3.8 grams NaCl (1 mole NaCl/58.54 grams) = 0.0650 moles NaCl Molarity = moles of solute/Liters of solution Molarity = 0.0650 moles NaCl/0.245 Liters = 0.27 M NaCl ----------------------


What is the molarity of sodium sulphate in a solution prepared by dissolving 15.5g in enough water to make 35ml of solution?

Molarity = moles of solute/volume of solution Find moles NaCl 55 grams NaCl (1mol NaCl/58.44 grams) = 0.941 moles NaCl Molarity = 0.941 moles NaCl/35 Liters = 0.027 Molarity NaCl ( sounds reasonable as 55 grams is not much in 35 Liters of water, which would be about 17.5 2 liter sodas )


What is the molarity of 6 moles of NaCl dissolved in 2 L of water?

6mol/2L


What is the molarity of 750 ml of NaCl solution that contains 21.04g of NaCl?

To calculate the molarity (M) of the NaCl solution, first find the number of moles of NaCl. The molar mass of NaCl is approximately 58.44 g/mol, so 21.04 g of NaCl is about 0.360 moles (21.04 g ÷ 58.44 g/mol). Molarity is defined as moles of solute per liter of solution; therefore, for 750 ml (0.750 L), the molarity is 0.360 moles ÷ 0.750 L = 0.480 M. Thus, the molarity of the NaCl solution is 0.480 M.


What is the molarity of 100mL of solution of water and 11.7g of Na Cl?

To find the molarity, first calculate the moles of NaCl using its molar mass (58.44 g/mol). Then, divide the moles of NaCl by the volume of solution in liters (0.1 L) to get the molarity in moles per liter.


What is the molarity of a 3000 liters solution containing 300 grams of NaCl?

Molarity = moles of solute/Liters of solution Find moles NaCl 300 grams NaCl (1 mole NaCl/58.44 grams) = 5.13347 moles NaCl Molarity = 5.13347 moles NaCl/3000 Liters = 1.71 X 10^-3 M sodium chloride ----------------------------------------


What is the molarity of 750 mL of NaCl solution that contains 21.04 g of NaCl?

To calculate the molarity of the NaCl solution, first convert the mass of NaCl to moles using its molar mass. The molar mass of NaCl is 58.44 g/mol. Then, divide the moles of NaCl by the volume of the solution in liters (750 mL = 0.75 L) to get the molarity. In this case, the molarity of the NaCl solution is 1.5 M.


What is the molarity of 6 moles (mol) of NaCl dissolved in 2 L of water?

The molarity of the solution is 3 M. This is calculated by dividing the moles of solute by the volume of solution in liters. In this case, 6 moles divided by 2 liters equals a molarity of 3 M.