Molarity = moles of solute/Liters of solution
Molarity = 6 Moles NaCl/2 Liters
= 3 M NaCl
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Molarity is defined as moles solute/liter of solution6 moles/2 liters solution = 3 molar NOTE: This assumes no volume change and 2L is the final volume of solution.
Get moles NaCl and change 245 ml to 0.245 Liters. 3.8 grams NaCl (1 mole NaCl/58.54 grams) = 0.0650 moles NaCl Molarity = moles of solute/Liters of solution Molarity = 0.0650 moles NaCl/0.245 Liters = 0.27 M NaCl ----------------------
6mol/2L
Molarity = moles of solute/Liters of solution Find moles NaCl 300 grams NaCl (1 mole NaCl/58.44 grams) = 5.13347 moles NaCl Molarity = 5.13347 moles NaCl/3000 Liters = 1.71 X 10^-3 M sodium chloride ----------------------------------------
To calculate the molarity of the NaCl solution, first convert the mass of NaCl to moles using its molar mass. The molar mass of NaCl is 58.44 g/mol. Then, divide the moles of NaCl by the volume of the solution in liters (750 mL = 0.75 L) to get the molarity. In this case, the molarity of the NaCl solution is 1.5 M.
The molarity of the solution is calculated by dividing the moles of solute (0.250 mol NaCl) by the liters of solution (2.25 L). Molarity = moles of solute / liters of solution Molarity = 0.250 mol / 2.25 L = 0.111 M
This molarity is 3 M.
Need moles NaCl first. 17.52 grams NaCl (1 mole NaCl/58.44 grams) = 0.29979 moles NaCl =====================Now. Molarity = moles of solute/Liters of solution ( 2000 ml = 2 Liters ) Molarity = 0.29979 mole NaCl/2 Liters = 0.1499 M NaCl ----------------------
Molarity is defined as moles solute/liter of solution6 moles/2 liters solution = 3 molar NOTE: This assumes no volume change and 2L is the final volume of solution.
Get moles NaCl and change 245 ml to 0.245 Liters. 3.8 grams NaCl (1 mole NaCl/58.54 grams) = 0.0650 moles NaCl Molarity = moles of solute/Liters of solution Molarity = 0.0650 moles NaCl/0.245 Liters = 0.27 M NaCl ----------------------
Molarity = moles of solute/volume of solution Find moles NaCl 55 grams NaCl (1mol NaCl/58.44 grams) = 0.941 moles NaCl Molarity = 0.941 moles NaCl/35 Liters = 0.027 Molarity NaCl ( sounds reasonable as 55 grams is not much in 35 Liters of water, which would be about 17.5 2 liter sodas )
6mol/2L
To calculate the molarity (M) of the NaCl solution, first find the number of moles of NaCl. The molar mass of NaCl is approximately 58.44 g/mol, so 21.04 g of NaCl is about 0.360 moles (21.04 g ÷ 58.44 g/mol). Molarity is defined as moles of solute per liter of solution; therefore, for 750 ml (0.750 L), the molarity is 0.360 moles ÷ 0.750 L = 0.480 M. Thus, the molarity of the NaCl solution is 0.480 M.
To find the molarity, first calculate the moles of NaCl using its molar mass (58.44 g/mol). Then, divide the moles of NaCl by the volume of solution in liters (0.1 L) to get the molarity in moles per liter.
Molarity = moles of solute/Liters of solution Find moles NaCl 300 grams NaCl (1 mole NaCl/58.44 grams) = 5.13347 moles NaCl Molarity = 5.13347 moles NaCl/3000 Liters = 1.71 X 10^-3 M sodium chloride ----------------------------------------
To calculate the molarity of the NaCl solution, first convert the mass of NaCl to moles using its molar mass. The molar mass of NaCl is 58.44 g/mol. Then, divide the moles of NaCl by the volume of the solution in liters (750 mL = 0.75 L) to get the molarity. In this case, the molarity of the NaCl solution is 1.5 M.
The molarity of the solution is 3 M. This is calculated by dividing the moles of solute by the volume of solution in liters. In this case, 6 moles divided by 2 liters equals a molarity of 3 M.