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What mass of water is needed to dissolve 292.5g of NaCl to produce 0.25 m aqueous solution?
m (molality)=moles of solute/kg of solvent To calculate moles of solute you convert 292.5 g of NaCl to moles of NaCl. So (292.5gNaCl)(1mole NaCl / 58.4gNaCl)= 5.0085 moles NaCl Now plug and chug. 0.25m=5.0085moles NaCl / x x=5.0085 moles NaCl /.25m x=20kg
A solution is made by dissolving 17.52g of nacl exactly 2000 ml what is the molarity of this solution?
concentration or molarity = number of moles/volume number of moles (n) = mass in grams of nacl/relative atomic mass of nacl n=17.52/(23+35.5) n = 0.2994872 mol volume = 2000/1000 = 2dm^3 molarity = 0.2994872/2 =0.15mol/dm^3
What is the molarity of 7.5 g NaCl in 500 mL of water?
.256
If 400.0 mL of 0.420 M NaCl are mixed with 110.0 mL of 0.240 M NaCl what is the molarity of the final solution?
In 400 ml of the 0.420 M NaCl there are 0.1680 moles of NaCl.In 110 ml of the 0.240 M NaCl there are 0.0264 moles of NaCl.There are 0.1944 moles of NaCl in 510 ml of solution. Dividing 0.1944 moles by 0.510 l gives 0.381 mole/l.So You get a 0.381 M NaCl.
The sterile solution used to rinse contact lenses can be made by dissolving 400 mg of NaCl in sterile water and diluting to 100 mL. what is the molarity of this solution?
First, find the moles of NaCl. Because you have 400 milligrams of NaCl convert to grams by dividing 1000mg. 400mg/1000mg = 0.400 grams of NaCl. Now we need to convert to moles. For every mole of NaCl there is 58.44 grams. (22.99g Na + 35.45 g Cl) so using stoichiometry (grams cancel) I get .0068 moles of NaCl. Conver 100 mL to L by dividing by 1000mL. Therefore there is .001 L in the solution. Molarity is moles per Liter. So 0.0068 mols of NaCl / 0.001 L = 6.84 M
Molarity of a solution of 6 moles mol of NaCl in 2L water?
Molarity = moles of solute/Liters of solution Molarity = 6 Moles NaCl/2 Liters = 3 M NaCl ========
What is the molarity of a solution of 55g of NaCl in 35L of water?
Molarity = moles of solute/volume of solution Find moles NaCl 55 grams NaCl (1mol NaCl/58.44 grams) = 0.941 moles NaCl Molarity = 0.941 moles NaCl/35 Liters = 0.027 Molarity NaCl ( sounds reasonable as 55 grams is not much in 35 Liters of water, which would be about 17.5 2 liter sodas )
What is the molarity of 6 moles of NaCl dissolved in 2 L water?
This molarity is 3 M.
What is the molarity of 6 moles (mol) of NaCl dissolved in 2 L of water?
This molarity is 3 mol/L.
What is the molarity of 6 moles of NaCl dissolved in 2L of water?
This is just easy. MOLARITY OF THIS COMPOUND IS 3MOLDM-3.
How many moles of NaCl are found in 0.25 Liters of 5.0 Molarity NaCl?
The answer is 1,25 moles.
What is the molarity of 6 moles of NaCl dissolved in 2 L of water?
6mol/2L
What is the molarity of 9 g of Na Cl in 1 L of solution?
Molarity = moles of solute/Liters of solution Find moles NaCl 9 grams NaCl (1 mole NaCl/58.44 grams) = 0.154 moles NaCl Molarity = 0.154 moles NaCl/1 Liter = 0.2 M sodium chloride -------------------------------
What is the mole concentration of 58.44g of NaCl in 1 L of water?
Molarity = moles of solute/Liters of solutionGet moles NaCl.58.44 grams NaCl (1 mole NaCl/58.44 grams)= 1 mole NaCl------------------Molarity = 1 mole NaCl/1 liter= 1 M NaCl========
What is the molarity of a solution consisting of 0.250 mol NaCl dissolved in 2.25 L of solution?
Molarity = moles of solute/Liters of solution Molarity = 0.250 moles NaCl/2.25 Liters = 0.111 M NaCl --------------------
What is the molarity of a 3000 liters solution containing 300 grams of NaCl?
Molarity = moles of solute/Liters of solution Find moles NaCl 300 grams NaCl (1 mole NaCl/58.44 grams) = 5.13347 moles NaCl Molarity = 5.13347 moles NaCl/3000 Liters = 1.71 X 10^-3 M sodium chloride ----------------------------------------
What is the concentration M of a NaCl solution prepared by dissolving 3.8 g of NaCl in sufficient water to give 245 mL of solution?
Get moles NaCl and change 245 ml to 0.245 Liters. 3.8 grams NaCl (1 mole NaCl/58.54 grams) = 0.0650 moles NaCl Molarity = moles of solute/Liters of solution Molarity = 0.0650 moles NaCl/0.245 Liters = 0.27 M NaCl ----------------------
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