Molarity = moles of solute/Liters of solution ( 300 ml = 0.300 Liters )
For our purposes, Moles of solute = Liters of solution * Molarity
Moles NaCl = 0.300 Liters * 0.15 M
= 0.05 moles NaCl
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By stoichiometry, 2 moles of sodium carbonate will produce 2 moles of sodium chloride. The molar mass of sodium chloride is approximately 58.44 g/mol, so 2 moles would weigh about 116.88 grams.
molecular formula for sodium chloride = NaClIf the mole (n) for NaCl = 5.3 moles, then the mole of sodium (Na) = 5.3 moles as well. 1 to 1 ratio mass = moles X molar mass m = 5.3 x 22.9 = 121.37 grams of sodium in 5.3 moles of sodium chloride
To find the number of moles in 42.5 grams of sodium chloride (NaCl), you first need to calculate the molar mass of NaCl, which is 58.44 g/mol. Then divide the given mass by the molar mass to get the number of moles. In this case, 42.5 grams divided by 58.44 g/mol is approximately 0.727 moles of sodium chloride.
To find the moles of sodium chloride solute in 155 grams of an 85.5% solution, first calculate the mass of sodium chloride present in the solution (mass percent x mass of solution). Then, convert the mass of sodium chloride to moles using its molar mass (58.44 g/mol). This will give you the number of moles of sodium chloride solute in the solution.
To convert moles to grams, you need to multiply the number of moles by the molar mass of the substance. The molar mass of sodium chloride (NaCl) is approximately 58.44 g/mol. Therefore, 4.40 moles of NaCl would be equal to 257.14 grams.
23.3772 grams are there in four tenths moles of sodium chloride
0,40 moles of sodium chloride contain 23,376 g.
By stoichiometry, 2 moles of sodium carbonate will produce 2 moles of sodium chloride. The molar mass of sodium chloride is approximately 58.44 g/mol, so 2 moles would weigh about 116.88 grams.
There are 9.3504 grams of Sodium Chloride. Calculations: 0.160 mol NaCl (58.44g/mol) = 9.3504g NaCl
10 moles of sodium chloride have 584,397 g.
molecular formula for sodium chloride = NaClIf the mole (n) for NaCl = 5.3 moles, then the mole of sodium (Na) = 5.3 moles as well. 1 to 1 ratio mass = moles X molar mass m = 5.3 x 22.9 = 121.37 grams of sodium in 5.3 moles of sodium chloride
To find the number of moles in 42.5 grams of sodium chloride (NaCl), you first need to calculate the molar mass of NaCl, which is 58.44 g/mol. Then divide the given mass by the molar mass to get the number of moles. In this case, 42.5 grams divided by 58.44 g/mol is approximately 0.727 moles of sodium chloride.
The mass is 467,52 g.
To find the moles of sodium chloride solute in 155 grams of an 85.5% solution, first calculate the mass of sodium chloride present in the solution (mass percent x mass of solution). Then, convert the mass of sodium chloride to moles using its molar mass (58.44 g/mol). This will give you the number of moles of sodium chloride solute in the solution.
To convert moles to grams, you need to multiply the number of moles by the molar mass of the substance. The molar mass of sodium chloride (NaCl) is approximately 58.44 g/mol. Therefore, 4.40 moles of NaCl would be equal to 257.14 grams.
If 4,00 is 4,00 moles the answer is 233,759 g NaCl.
To find the number of grams in 3.80 mol of sodium chloride, you need to multiply the number of moles by the molar mass of sodium chloride. The molar mass of sodium chloride (NaCl) is 58.44 g/mol. Therefore, 3.80 mol * 58.44 g/mol = 222.13 grams of sodium chloride.