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What is the molarity of a 3000 liters solution containing 300 grams of NaCl?
Wiki User
∙ 13y ago
Molarity = moles of solute/Liters of solution
Find moles NaCl
300 grams NaCl (1 mole NaCl/58.44 grams) = 5.13347 moles NaCl
Molarity = 5.13347 moles NaCl/3000 Liters
= 1.71 X 10^-3 M sodium chloride
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∙ 13y ago
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