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What is the molarity of a solution of 73 g of HCL in 2 liters of water?
Wiki User
∙ 11y ago
Molarity = moles of solute/Liters of solution
So, get moles HCl.
73 grams HCl (1 mole HCl/36.458)
= 2.00 moles HCl
---------------------------
Molarity = 2.00 moles HCl/2 Liters
= 1 M HCl
=======
Wiki User
∙ 11y ago
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What is the molarity of a solution in which 0.597 moles of HCl are dissolved in 0.169 liters of solution?
Molarity = moles of solute/liters of solution Molarity = 0.597 moles HCl/0.169 liters = 3.53 M HCl ------------------
What is the molarity of a solution that contains 31.0 grams of HCl in 500cm3 of solution?
31 grams HCl (1mol/36.458g ) = 0.850 moles 500cm^3 = 0.50 Liters Molarity = moles of solute/liters of solution Molarity = 0.850mol/0.50L = 1.7 Molarity
How many moles of HCl are present in 40ml of a 0.035M solution?
Molarity = moles of solute/Liters of solution (40 ml = 0.04 Liters) algebraically manipulated, Moles of solute = Liters of solution * Molarity Moles HCl = (0.04 Liters)(0.035 M) = 0.0014 moles HCl ==============
Molarity of a solution of 6 moles mol of NaCl in 2L water?
Molarity = moles of solute/Liters of solution Molarity = 6 Moles NaCl/2 Liters = 3 M NaCl ========
How many moles of solute are in 50 mL of a 12 M HCl solution?
Molarity = moles of solute/Liters of solution ( 50 ml = 0.05 Liters ) 12 M HCl = moles HCl/0.05 Liters = 0.60 moles HCl
What is the molarity of a solution in which 0.597 moles of HCl are dissolved in 0.169 liters of solution?
Molarity = moles of solute/liters of solution Molarity = 0.597 moles HCl/0.169 liters = 3.53 M HCl ------------------
What is the molarity of a solution that contains 31.0 grams of HCl in 500cm3 of solution?
31 grams HCl (1mol/36.458g ) = 0.850 moles 500cm^3 = 0.50 Liters Molarity = moles of solute/liters of solution Molarity = 0.850mol/0.50L = 1.7 Molarity
How many moles of HCl are present in 40ml of a 0.035M solution?
Molarity = moles of solute/Liters of solution (40 ml = 0.04 Liters) algebraically manipulated, Moles of solute = Liters of solution * Molarity Moles HCl = (0.04 Liters)(0.035 M) = 0.0014 moles HCl ==============
Molarity of a solution of 6 moles mol of NaCl in 2L water?
Molarity = moles of solute/Liters of solution Molarity = 6 Moles NaCl/2 Liters = 3 M NaCl ========
How many moles of solute are in 50 mL of a 12 M HCl solution?
Molarity = moles of solute/Liters of solution ( 50 ml = 0.05 Liters ) 12 M HCl = moles HCl/0.05 Liters = 0.60 moles HCl
What volume of 4.00 M Hcl solution contains 0.150 mol Hcl?
Molarity = moles of solute/Liters of solutionOr, for our purposes....,Liters of solution (volume) = moles of solute/MolarityVolume (liters) = 0.150 moles HCl/4.00 M HCl= 0.0375 liters = 37.5 milliliters======================
What is the molarity of the HCl solution if 240 ml of the HCl solution reacts with magnesium to produce 4.60 L of HCl gas measured at STP?
We can use PV = nRT to find moles of HCl (1 atm)(4.60 L) = n(0.08206 L*atm/mol*K)(298.15 K) moles HCl = 0.188 moles Molarity = moles of solute/Liters of solution Molarity = 0.188 moles HCl/0.240 liters = 0.783 Molar HCl =============
What is the pH of a solution that contains 0.10 mole of HCI in a voulme of 100.0l?
100 Liters? I will assume as much. Molarity = moles of solute/Liters of solution Molarity = 0.10 mole HCl/100.0 Liters = 0.001 M HCl -------------------------now, to find pH - log(0.001 M HCl) = 3 pH -----------------so, your acid is of 3 pH, which is to be expected at the volume od solution
What is the molarity of a solution prepared by dissolving 1.56 grams of gaseous HCl in enough water to make 26.8 mL of solution?
Find moles of HCl first. 1.56 grams HCl (1mole HCl/36.458 grams) = 0.0428 moles HCl Molarity = moles of solute/volume of solution Molarity = 0.0428 moles/26.8 ml = 0.00160 milli-Molarity, or more to the point; = 1.60 X 10^-6 Molarity of HCl
How many moles of HCl are present in 0.250 L of 0.400 M HCl?
Molarity = moles of solute/liters of solution, so... 0.400M HCl (X mols HCl/0.250L ) = 0.100 moles HCl
What If enough water is added to 5 g of HCl to make 1 liter of solution what is the pH?
Find moles HCl. 5 g HCl (1 mole HCl/36.450 grams) = 0.1372 moles HCl Now, Molarity = moles of solute/Liters of solution Molarity = 0.1372 moles HCl/1 liter = 0.1372 M HCl Then. -log(0.1372 M HCl) = 0.9 pH ( you might call it 1, but pH can be off the scale ) -----------
How many ml of a 0.60m hcl soloution are needed to neutralize 2.5g of sodium carabonate?
Balanced equation first, last and always! Na2CO3 + 2HCl - > 2NaCl + CO2 + H2O 2.5 g Na2CO3 ( 1 mole Na2CO3/105.99 g)(2 mole HCl/1 mole Na2CO3) 0.04717 moles HCl -------------------------Now, Molarity = moles of solute/liters of solution or, for our purposes liters of solution = moles of solute/Molarity Liters HCl = 0.04717 moles HCl/0.60 M HCl = 0.0786 liters (1000 milliliters/1 liter) = 78. 6 milliliters HCl solution needed
