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What is the concentration of a solution if it has 25 g of salt dissolved in 400 mL of water?
To find the concentration of the solution, you can use the formula for concentration (C), which is mass (m) divided by volume (V). Here, the mass of salt is 25 g and the volume of water is 400 mL. Therefore, the concentration is C = 25 g / 0.4 L = 62.5 g/L. Thus, the concentration of the solution is 62.5 g/L.
300.0 Ml of water is added to .40 L of a .400 M Na2CrO4 solution what is the molarity of the resulting solution?
300.0 ml of water is added to .40 L of a .400 M Na2CrO4 solution what is the molarity of the resulting solution? Na2CrO4 = 2 Cr +Cr + 4 O's Molar mass = (2*23 + 52 + (4*16) = 162 A .400 M N Na2CrO4 solution has .400 moles of Na2CrO4 in a liter of water. .400 moles of Na2CrO4 = 0.400 * 162 = 64.8 grams of Na2CrO4 in a liter of water. Since you only have .40 L, you have 64.8 grams/liter * 0.4L = 25.92 grams of Na2CrO4 in 0.4 liter of solution. When you add 300.0 ml of water, you have total of 700 ml of solution. You still have 25.92 grams of Na2CrO4, but now you have 700 ml of solution. Molarity = moles of solute per liter of solution. Moles of solute = grams of solute ÷ Molar mass of solute Moles of solute = 25.92 ÷ 162 = 0.16 moles of Na2CrO4. Molarity = 0.16 moles of Na2CrO4 ÷ 0.700 L of solution. Molarity = 0.23 M
The pressure acting on 50 cubic meters of gas is raised from 200 kPa to 400 kPa The temperature remains constant What is the new volume?
Using Boyle's Law, we can calculate the new volume by dividing the initial pressure by the final pressure and multiplying it by the initial volume. New Volume = (Initial Pressure / Final Pressure) * Initial Volume = (200 kPa / 400 kPa) * 50 cubic meters = 25 cubic meters.
What volume is needed to store 0.050 moles of helium gas at 202.6 kPa and 400 K?
The volume is 0,82 L.
How would you prepare 20 ml of a 1 to 400 dilution?
If accuracy is not a problem the most simple way to produce 20 ml of a 1:400 dilution is to take 1:400 of 20 ml (i.e. 0.05 ml) of the original solution and add 19.95 ml of liquid. As pipettes are the most precise close to their maximum uptake volume and micro-pipettes are inherently much less precise than pipettes for larger volumes I'd do a two-step dilution. 1. step: 1.000 ml of original solution with 1 ml pipette + 4 times 4.750 ml with 5 ml pipette 2. step: 1.000 ml of solution from step 1 + 4 times 4.750 ml with 5 ml pipette.
How do you calculate the volume in milliliters of a 0.61M sodium nitrate solution that contains 400mmol of sodium nitrate?
By definition, a 0.61M sodium nitrate solution contains 0.61 moles of sodium nitrate per liter, which is equivalent to 0.61 mmol/ml. Therefore, the volume of this solution required to contain 400mmol is 400/0.61 or 6.6 X 102 ml, to the justified number of significant digits.
What is the percent mv of a water solution that contains 60 g of calcium chloride CaCl2 and that has a volume of 400 mL?
To calculate the percent mass/volume (m/v) of the solution, you would divide the mass of the solute (CaCl2) by the volume of the solution and then multiply by 100. In this case, the mass of CaCl2 is 60 g and the volume of the solution is 400 mL. So, the percent m/v would be (60g/400mL) x 100 = 15% m/v.
What volume of 2.85M NaCl solution contains .400 mol NaCl?
0,4 mol NaCl is 23,376 g.2,85 mol NaCl is 166,554 g to 1L.140 mL solution NaCl 2,85 M contain 0,4 mol NaCl.
What is the volume percent concentration of propanol in a solution made by mixing 100 mL of propanol with 0.30 L of water?
To calculate the volume percent concentration of propanol in the solution, we first need to find the total volume of the solution. This would be the sum of the volumes of propanol and water: 100 mL + 300 mL = 400 mL. The volume percent concentration of propanol in the solution is then calculated by dividing the volume of propanol by the total volume of the solution and multiplying by 100: (100 mL / 400 mL) * 100 = 25%. Therefore, the propanol concentration in the solution is 25% (v/v).
What is the concetration of 400 ml of 0.5 M HCl?
The concentration of a solution is given by the formula: concentration = moles of solute / volume of solution in liters. However, to determine the concentration in this case, we need to know the moles of HCl in the solution. Given that the concentration is 0.5 M, it means there are 0.5 moles of HCl in every liter of solution. To find out how many moles are in 400 ml (0.4 L) of 0.5 M HCl solution, we use the formula: moles = concentration x volume. moles = 0.5 M x 0.4 L = 0.2 moles. Therefore, the concentration of 400 ml of 0.5 M HCl solution is 0.5 M.
What is the percent of a water solution that contains 60 g of calcium chloride and that has a mass of 400 g?
The percent of a solution is calculated by dividing the mass of the solute by the mass of the solution and multiplying by 100. In this case, the percent of the water solution containing 60 g of calcium chloride in a 400 g solution would be (60 g / 400 g) * 100 = 15%.
What weight of glucose is required to prepare 2 L of a 5 percent weight to volume solution?
400 mls would require 40g of glucose for a 10% solution and thus 20g for a 5% solution.
What is the concentration of a solution if it has 25 g of salt dissolved in 400 mL of water?
To find the concentration of the solution, you can use the formula for concentration (C), which is mass (m) divided by volume (V). Here, the mass of salt is 25 g and the volume of water is 400 mL. Therefore, the concentration is C = 25 g / 0.4 L = 62.5 g/L. Thus, the concentration of the solution is 62.5 g/L.
How many milligrams of an active ingredient are needed to make 400 ml of a 1 in 1000 solution?
It is not clear whether the strength of the solution is given in terms of mass/mass or volume/volume (or mass/volume). Without that information, it is not possile to answer the question. Depending on which one you may need the density of the active ingredient or of the solvent to convert between mass and volume of that component.
A chemist has one solution that is 80 percent acid and another solution that is 30 percent acid how much of the second 30 percent solution is needed to make a 400L that is 62 percent acid?
.80x+.30y=400*.62 .80x+.30y=248 This is equation one. x+y=400 x=400-y This is the second equation. .80(400-y)+.30y=248 320-.80y+.30y=248 -.50y=-72 Y=144 X=256 CHECK .80(256)+.30(144)=400(.62) 204.8+43.2=248 248=248
What is the volume of a box measuring 8mm10cm5cm?
400
What is the final concentration if 75.0 mL of a 3.50 M glucose solution is diluted to a volume of 400 mL?
A 1 mole glucose solution means that there would be 1 mol/liter. There is only .075 liters, so there is only .075 moles present. .075 moles in 400 milliliters is a .075 to .4 ratio. By expanding the ratio, it is found that there are .1875 moles to 1 liter, making the final concentration 0.1875 M.
