400 mls would require 40g of glucose for a 10% solution and thus 20g for a 5% solution.
To prepare a 10% glucose solution, you would mix 10 grams of glucose with enough water to make a total solution volume of 100 ml. This means the final solution would contain 10 grams of glucose and 90 ml of water.
I don't think you can. The maximum solubility of glucose in water is 91% w/v. That would mean dissolving 91g of glucose in 100ml of water. for a 100% solution you would need to dissolve 100g in 100ml, and you cant do it under normal conditions.
To prepare a 40% potassium chloride solution in 100g of water, you would need to calculate the mass of potassium chloride required. Since the solution is 40% potassium chloride, that means 40g of the total solution mass must be potassium chloride. Therefore, you would need to add 40g of potassium chloride to the 100g of water to prepare the solution.
To prepare the 0.50M acetic acid solution, you can use the formula C1V1 = C2V2. Plugging in the values, you get (2.5M)(V1) = (0.50M)(100.0mL). Solving for V1 gives V1 = 20.0 mL. Therefore, 20.0 milliliters of the 2.5M stock solution is required to prepare 100.0 milliliters of the 0.50M acetic acid solution.
To prepare a 0.5 M glucose solution in 1 liter of water, you would need to dissolve 90.08 grams of glucose in enough water to make up the total volume of 1 liter. Start by weighing out 90.08 grams of glucose, add it to a container, and then add enough water to make the total volume up to 1 liter.
To prepare a 50mm glucose solution, you would need to dissolve 9g of glucose in enough water to make 100mL of solution. This would give you a solution with a concentration of 50mm (millimolar).
To prepare a 5% NaCl solution, you will need 200 grams of NaCl for 4000 mL (4 L) of solution. This is calculated as 5% of 4000 mL, which equals 200 grams.
To prepare a 10% glucose solution, you would mix 10 grams of glucose with enough water to make a total solution volume of 100 ml. This means the final solution would contain 10 grams of glucose and 90 ml of water.
I don't think you can. The maximum solubility of glucose in water is 91% w/v. That would mean dissolving 91g of glucose in 100ml of water. for a 100% solution you would need to dissolve 100g in 100ml, and you cant do it under normal conditions.
To prepare a saturated solution of glucose, simply add an excess of glucose to a specific amount of water at a certain temperature while continuously stirring until no more glucose dissolves. The solution is saturated when no more glucose can be dissolved and some solid remains at the bottom.
See the two Related Questions to the left for the answer.The first is how to prepare a solution starting with a solid substance (and dissolving it). The second question is how to prepare a solution by diluting another solution.
pharmacist
25
To prepare a 40% potassium chloride solution in 100g of water, you would need to calculate the mass of potassium chloride required. Since the solution is 40% potassium chloride, that means 40g of the total solution mass must be potassium chloride. Therefore, you would need to add 40g of potassium chloride to the 100g of water to prepare the solution.
To calculate the mass of magnesium needed, use the formula: mass of solute = volume of solution (ml) x percentage concentration / 100. In this case, it would be 60 ml x 20% = 12 g or 12,000 mg of magnesium will be required to prepare 60 ml of a 20% solution.
125 ml 500(ml) * 0.05 = 25 25 / 0.20 = 125
To prepare the 0.50M acetic acid solution, you can use the formula C1V1 = C2V2. Plugging in the values, you get (2.5M)(V1) = (0.50M)(100.0mL). Solving for V1 gives V1 = 20.0 mL. Therefore, 20.0 milliliters of the 2.5M stock solution is required to prepare 100.0 milliliters of the 0.50M acetic acid solution.