14.575 round is 14.6 g
It depends on the final solution Volume you want to prepare. For 100ml of a 6M NaCL solution, you add 35.1g of NaCl to water until you reach 100ml. Dissolve and autoclave for 15 mins.
Oh honey, it's not rocket science. Just measure out 30 grams of table salt and dissolve it in enough water to make 100 grams of solution. Voila, you've got yourself a 30% NaCl solution. Just don't go drinking it thinking it's a margarita, okay?
the formula is no. moles is mass / molecular mass. As the number of moles is 1, the mass required will be exactly the same as the molecular mass, which is 58.32g
600 mL of 0,9 % sodium chloride: 6 x 0,9 = 5,4 grams NaCl
By definition, 1 liter of a 4 M solution must contain 4 moles of the solute. Because solutions are homogeneous mixtures and 250 ml is one quarter of a liter, the amount of KCl required is 1 mole. The gram molar mass* of KCl is 74.55 grams; this is therefore the amount of KCl required.** __________________________________ *Because KCl is an ionic rather than a molecular compound, its "gram molar mass" should preferably be called its "gram formula unit mass". **Strictly according to the rules of significant digits, this answer should be written as "7 X 10" grams, because the datum "4M" needed to calculate the answer contains only one significant digit.
See the two Related Questions to the left for the answer.The first is how to prepare a solution starting with a solid substance (and dissolving it). The second question is how to prepare a solution by diluting another solution.
To prepare a 3% solution of sulfosalicylic acid, you would need 30 grams of sulfosalicylic acid for every 1 liter of solution.
4314.9 grams
1% solution = 1 gram per 100 mL, 10 grams per liter 20 grams
400 mls would require 40g of glucose for a 10% solution and thus 20g for a 5% solution.
To prepare a 2% solution in 3 liters, you would need 60 grams of the drug. This is calculated by multiplying the volume (3 liters) by the percentage (2%) and converting the result to grams. 3 liters x 2% = 60 grams.
You need 50 g of this drug.
40.8 grams
To prepare a 5% potassium iodide solution, weigh 5 grams of potassium iodide and dissolve it in 100 mL of water. Stir until the potassium iodide is completely dissolved to achieve a 5% solution.
To prepare a 30% NaOH solution, you would mix 30 grams of NaOH with enough water to make 100 grams of final solution. Be sure to use caution when handling NaOH as it is a caustic substance and can cause skin and eye irritation.
To prepare a 500mM KCl solution, you would need to dissolve 74.55 grams of KCl in enough solvent to make 1 liter of solution.
To prepare a 0.20 M solution of I2 in CCl4, you would need to calculate the moles of I2 required first. Molarity (M) = moles of solute / liters of solution. Since you know the molarity and volume of the solution, you can calculate the moles of I2 required and then convert that to grams using the molar mass of I2.