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How many grams are KCl are required to prepare 250 ml of a 4M solution?
Wiki User
∙ 10y ago
By definition, 1 liter of a 4 M solution must contain 4 moles of the solute. Because solutions are homogeneous mixtures and 250 ml is one quarter of a liter, the amount of KCl required is 1 mole. The gram molar mass* of KCl is 74.55 grams; this is therefore the amount of KCl required.**
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*Because KCl is an ionic rather than a molecular compound, its "gram molar mass" should preferably be called its "gram formula unit mass".
**Strictly according to the rules of significant digits, this answer should be written as "7 X 10" grams, because the datum "4M" needed to calculate the answer contains only one significant digit.
Wiki User
∙ 10y ago
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How many grams of KCl are required to prepare 2.25L of a 0.75m KCl solution?
Molarity = moles of solute/Liters of solution 0.75 M KCl = moles KCl/2.25 Liters = 1.6875 moles KCl (74.55 grams/1 mole KCl) = 126 grams of KCl needed
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How many grams of KCl are required to prepare 2.25L of a 0.75m KCl solution?
Molarity = moles of solute/Liters of solution 0.75 M KCl = moles KCl/2.25 Liters = 1.6875 moles KCl (74.55 grams/1 mole KCl) = 126 grams of KCl needed
How many grams of NaCl would be required to make 6M solution?
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How many grams of NaCl are required to prepare 4000 mL of 5 percent solution?
14.575 round is 14.6 g
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