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Molarity = moles of solute/Liters of solution
0.75 M KCl = moles KCl/2.25 Liters
= 1.6875 moles KCl (74.55 grams/1 mole KCl)
= 126 grams of KCl needed
74 grams
9.13
1 m = 100 cm or 0.01 m = 1 cm so 0.075 m = 7.5 cm