Since the molecular weight of HCl is 36.46g/mole, 1 mole of HCl contains 36.46g. 1 liter of a 0.5M solution will have 18.23g of HCl. 400 ml will have 7.292g of HCl.
To make 0.25N HCl from 1.00N HCl, you would need to dilute the 1.00N HCl solution by adding three parts of water for every part of the original solution. For example, you can mix 1 mL of 1.00N HCl with 3 mL of water to obtain 0.25N HCl solution.
V = volume, M = molarity V1M1=V2M2 (25 mL)(0.0010 M) = (x)(0.010 M) x = (25 mL)(0.0010 M)/(0.010 M) x = 2.5 mL To make a 25 mL 0.0010 M HCl solution with 0.010 M HCl, you would measure out 2.5 mL of the 0.010 M HCl in a 25 mL graduated cylinder (or laboratory equipment of your choice) and then add 22.5 mL of distilled water.
44.5 ml HCl TAKE AND DILUTE UP TO 1000 ML WATER MAKE A 0.5 M HCl SOLUTION
By dilution (1000x) with water: Take 1.0 mL 1.0N HCl and add up to 1000 mL with pure water.
To prepare 100 mL of 1.0 M HCl from a 3.0 M stock solution, you can use the formula: (M_1V_1 = M_2V_2). Solving for V1: (3.0 M)(V1 mL) = (1.0 M)(100 mL), thus V1 = 33.3 mL. So, you would need to measure out 33.3 mL of the 3.0 M HCl solution and then dilute it to 100 mL to obtain 1.0 M HCl.
100 M HCl don't exist.
To make 0.25N HCl from 1.00N HCl, you would need to dilute the 1.00N HCl solution by adding three parts of water for every part of the original solution. For example, you can mix 1 mL of 1.00N HCl with 3 mL of water to obtain 0.25N HCl solution.
0.0747mol/L of HCL 1.81mol/L of water
Mix 125 mL 0,1 N HCl with 125 mL water.
V = volume, M = molarity V1M1=V2M2 (25 mL)(0.0010 M) = (x)(0.010 M) x = (25 mL)(0.0010 M)/(0.010 M) x = 2.5 mL To make a 25 mL 0.0010 M HCl solution with 0.010 M HCl, you would measure out 2.5 mL of the 0.010 M HCl in a 25 mL graduated cylinder (or laboratory equipment of your choice) and then add 22.5 mL of distilled water.
44.5 ml HCl TAKE AND DILUTE UP TO 1000 ML WATER MAKE A 0.5 M HCl SOLUTION
By dilution (1000x) with water: Take 1.0 mL 1.0N HCl and add up to 1000 mL with pure water.
520 ml of HCl in 480 ml of water=1000ml = 5 N
To prepare 100 mL of 1.0 M HCl from a 3.0 M stock solution, you can use the formula: (M_1V_1 = M_2V_2). Solving for V1: (3.0 M)(V1 mL) = (1.0 M)(100 mL), thus V1 = 33.3 mL. So, you would need to measure out 33.3 mL of the 3.0 M HCl solution and then dilute it to 100 mL to obtain 1.0 M HCl.
For 1 Liter you should take 88.8 mL concentrated HCL (be carefull) and add it to 900 mL water, and finally - after mixing- fill this up to 1000 mL with distilled water. (REMEMBER: ALWAYS ADD ACID TO WATER! -1N in 250 ml : add 22.2 mL to about (or less than) 225 mL water and dilute to final volume = 0.25L
400 L/250 mL = 400,000 mL / 250 mL = 1600 bottles.400 L/250 mL = 400,000 mL / 250 mL = 1600 bottles.400 L/250 mL = 400,000 mL / 250 mL = 1600 bottles.400 L/250 mL = 400,000 mL / 250 mL = 1600 bottles.
To find the moles of HCl, first calculate the millimoles of HCl in 50 mL: 4.0 mol/L * 50 mL = 200 mmol. Then convert millimoles to moles by dividing by 1000: 200 mmol / 1000 = 0.2 moles of HCl. Therefore, there are 0.2 moles of HCl in 50 mL of 4.0 M HCl.