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How many moles of HCl are present in 40ml of a 0.035M solution?
Molarity = moles of solute/Liters of solution (40 ml = 0.04 Liters) algebraically manipulated, Moles of solute = Liters of solution * Molarity Moles HCl = (0.04 Liters)(0.035 M) = 0.0014 moles HCl ==============
What is the molarity of a solution in which 0.597 moles of HCl are dissolved in 0.169 liters of solution?
Molarity = moles of solute/liters of solution Molarity = 0.597 moles HCl/0.169 liters = 3.53 M HCl ------------------
How many moles are dissolved in 200 ml of 0.100 M HCl?
There are 0.020 moles of HCl dissolved in 200 ml of 0.100 M HCl solution. This is calculated by multiplying the volume of the solution by the molarity of the solute.
What is the molarity of a solution of 73 g of HCL in 2 liters of water?
Molarity = moles of solute/Liters of solutionSo, get moles HCl.73 grams HCl (1 mole HCl/36.458)= 2.00 moles HCl---------------------------Molarity = 2.00 moles HCl/2 Liters= 1 M HCl=======
How many moles of HCl are present in 0.250 L of 0.400 M HCl?
Molarity = moles of solute/liters of solution, so... 0.400M HCl (X mols HCl/0.250L ) = 0.100 moles HCl
How many moles of HCl are present in 40ml of a 0.035M solution?
Molarity = moles of solute/Liters of solution (40 ml = 0.04 Liters) algebraically manipulated, Moles of solute = Liters of solution * Molarity Moles HCl = (0.04 Liters)(0.035 M) = 0.0014 moles HCl ==============
What volume of 4.00 M Hcl solution contains 0.150 mol Hcl?
Molarity = moles of solute/Liters of solutionOr, for our purposes....,Liters of solution (volume) = moles of solute/MolarityVolume (liters) = 0.150 moles HCl/4.00 M HCl= 0.0375 liters = 37.5 milliliters======================
What is the molarity of a solution in which 0.597 moles of HCl are dissolved in 0.169 liters of solution?
Molarity = moles of solute/liters of solution Molarity = 0.597 moles HCl/0.169 liters = 3.53 M HCl ------------------
How many moles are dissolved in 200 ml of 0.100 M HCl?
There are 0.020 moles of HCl dissolved in 200 ml of 0.100 M HCl solution. This is calculated by multiplying the volume of the solution by the molarity of the solute.
What is the molarity of a solution of 73 g of HCL in 2 liters of water?
Molarity = moles of solute/Liters of solutionSo, get moles HCl.73 grams HCl (1 mole HCl/36.458)= 2.00 moles HCl---------------------------Molarity = 2.00 moles HCl/2 Liters= 1 M HCl=======
How many moles of HCl are present in 0.250 L of 0.400 M HCl?
Molarity = moles of solute/liters of solution, so... 0.400M HCl (X mols HCl/0.250L ) = 0.100 moles HCl
How many equivalents are there in 15 ml of concentrated Hcl which is approximately 12 molar in concentration?
molarity = number of moles of solute / volume of solution number of moles of solute = molarity x volume of solution number of moles of solute = 12 (mole/L) x 15/1000 (L) number of moles of solute = 0.18 mole
What is the mole fraction of HCl in an aqueous solution that is 27.2 percent HCl by weight?
To find the mole fraction of HCl in the solution, we first need to calculate the molar mass of HCl (H=1g/mol, Cl=35.5g/mol). Then, determine the number of moles of HCl in 100g of the solution. Finally, calculate the mole fraction of HCl by dividing the moles of HCl by the total moles of solute and solvent in the solution.
When a solution is diluted does it change the number of moles dissolved?
The number of moles of a solute will not change as a solution is diluted, however, the concentration of the solute will decrease. If you were to evaporate the water from the diluted solution, you would have the same number of moles of solute as when you started. You can test this by comparing the mass of the solute before producing the solution to the mass of the solute after the solution was diluted. The two masses should be the same.
How many moles of HCl are present in a 0.0250 L solution?
1. First, remember definition of M (moles), M = moles of species / L. 0.33 M = 0.33 moles HCl / L 2. Then, multiple your volume by the molar concentration: 0.33 moles HCl / L x 0.70 L = 0.231 moles HCl or you can say n=CONCENTRATION multiply by VOLUME(HCl) which gives 2310 mol HCl It's helpful to carry the units with your calculations. That way you can check that numerators and denominators cancel to give you the units of your answer.
What is the concetration of 400 ml of 0.5 M HCl?
The concentration of a solution is given by the formula: concentration = moles of solute / volume of solution in liters. However, to determine the concentration in this case, we need to know the moles of HCl in the solution. Given that the concentration is 0.5 M, it means there are 0.5 moles of HCl in every liter of solution. To find out how many moles are in 400 ml (0.4 L) of 0.5 M HCl solution, we use the formula: moles = concentration x volume. moles = 0.5 M x 0.4 L = 0.2 moles. Therefore, the concentration of 400 ml of 0.5 M HCl solution is 0.5 M.
What is the molarity of the HCl solution if 240 ml of the HCl solution reacts with magnesium to produce 4.60 L of HCl gas measured at STP?
We can use PV = nRT to find moles of HCl (1 atm)(4.60 L) = n(0.08206 L*atm/mol*K)(298.15 K) moles HCl = 0.188 moles Molarity = moles of solute/Liters of solution Molarity = 0.188 moles HCl/0.240 liters = 0.783 Molar HCl =============
