1. First, remember definition of M (moles), M = moles of species / L.
0.33 M = 0.33 moles HCl / L
2. Then, multiple your volume by the molar concentration:
0.33 moles HCl / L x 0.70 L = 0.231 moles HCl or you can say n=CONCENTRATION multiply by VOLUME(HCl) which gives 2310 mol HCl
It's helpful to carry the units with your calculations. That way you can check that numerators and denominators cancel to give you the units of your answer.
The molarity of a solution refers to the concentration of a solute in moles per liter of solution. It is a measure of how many moles of solute are present in a given volume of the solution.
To find the moles of solute, multiply the volume of the solution in liters (1.25 L) by the molarity of the solution (0.75 mol/L). Therefore, the moles of NaNO3 in 1.25 L of 0.75M solution is 0.9375 moles.
To find the number of moles of H ions in the solution, first calculate the moles of HNO3 using the given concentration and volume. Since each mole of HNO3 yields 1 mole of H ions in solution, the number of moles of H ions is the same as the moles of HNO3. Therefore, in this case, there are 0.4512 moles of H ions present in the solution.
Amount of HCl = 700/1000 x 0.33 = 0.231 moles
Molarity = moles of solute/Liters of solution (40 ml = 0.04 Liters) algebraically manipulated, Moles of solute = Liters of solution * Molarity Moles HCl = (0.04 Liters)(0.035 M) = 0.0014 moles HCl ==============
The molarity of a solution refers to the concentration of a solute in moles per liter of solution. It is a measure of how many moles of solute are present in a given volume of the solution.
The answer is 0,0509 mole.
There would be 0.1 moles of NaCl present in 1 liter of a 0.1M solution of sodium chloride. This is based on the definition of molarity which is moles of solute per liter of solution.
The answer is 0,1 mol.
To find the moles of solute, multiply the volume of the solution in liters (1.25 L) by the molarity of the solution (0.75 mol/L). Therefore, the moles of NaNO3 in 1.25 L of 0.75M solution is 0.9375 moles.
To find the number of moles of H ions in the solution, first calculate the moles of HNO3 using the given concentration and volume. Since each mole of HNO3 yields 1 mole of H ions in solution, the number of moles of H ions is the same as the moles of HNO3. Therefore, in this case, there are 0.4512 moles of H ions present in the solution.
Amount of HCl = 700/1000 x 0.33 = 0.231 moles
Molarity = moles of solute/Liters of solution (40 ml = 0.04 Liters) algebraically manipulated, Moles of solute = Liters of solution * Molarity Moles HCl = (0.04 Liters)(0.035 M) = 0.0014 moles HCl ==============
Molarity = moles of solute/Liters of solution ( 75.0 ml = 0.075 Liters ) Algebraically manipulate, moles of solute = Liters of solution * Molarity Moles KMnO4 = (0.075 Liters)(0.0950 M) = 7.13 X 10 -3 moles KMnO4 ------------------------------------
The molarity of a solution indicates the concentration of a solute in moles per liter of solution. It provides information about how many moles of a substance are present in a given volume of solution which helps in understanding the strength or dilution of the solution.
You need the molar solution to get the number of moles present in 6.52g of Zinc Sulfate.
To find the number of moles of KBr in the solution, first calculate the number of moles of KBr in the 25 mL solution using the given concentration and volume. $$moles = concentration \times volume$$ Then, multiply the moles by the molecular weight of KBr to get the mass of KBr in the solution if needed.