Molarity = moles of solute/Liters of solution ( 75.0 ml = 0.075 Liters )
Algebraically manipulate,
moles of solute = Liters of solution * Molarity
Moles KMnO4 = (0.075 Liters)(0.0950 M)
= 7.13 X 10 -3 moles KMnO4
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Find the mass(in grams) of potassium permanganate, KMnO4, present in 500 ml of a 3.00 M solution.
1 mol = 118.94 1 mol / 118.94 = 1.70 / x G = 202.10g
Molarity = moles of solute/Liters of solution (40 ml = 0.04 Liters) algebraically manipulated, Moles of solute = Liters of solution * Molarity Moles HCl = (0.04 Liters)(0.035 M) = 0.0014 moles HCl ==============
Molarity = moles of solute/Liters of solution ( 22.0 ml = 0.022 Liters ) moles of solute = Molarity * Liters of solution Moles of NaCl = 0.500 M * 0.022 Liters = 0.011 moles of sodium chloride -------------------------------------------
The Stoichiometry of molar concentration follows this simple formula: Mol = Volume (dm³) × Molar Concentration (mol/dm³) Hence: Molar Concentration (mol/dm³) = Number of moles (mol)/ Volume (dm³)
Molarity = moles of solute/Liters of solution ( 20.0 ml = 0.02 Liters ) moles of solute = Liters of solution * Molarity 0.02 Liters * 0.800 M MgCl2 = 0.016 moles MgCl2 -------------------------------
The solubility of potassium permanganate in water at 2o 0C is 64 g/l (or 32 g/0,5 L).The molar mass of KMnO4 is 158,034 g and 0,35 moles KMnO4 is equal to 55,312 g.So it is not possible to dissolve o,35 moles KMnO4 in 0,5 L.
1 mol = 118.94 1 mol / 118.94 = 1.70 / x G = 202.10g
The answer is 0,o276 moles.
Molarity = moles of solute/Liters of solution (40 ml = 0.04 Liters) algebraically manipulated, Moles of solute = Liters of solution * Molarity Moles HCl = (0.04 Liters)(0.035 M) = 0.0014 moles HCl ==============
The compound potassium permanganate has chemical formula KMnO4 Molecular mass of KMnO4 = 39.1 + 54.9 + 4(16.0) = 158.0 Mass of KMnO4 = amount of KMnO4 x Molecular mass of KMnO4 = 2.55 x 158.0 = 403g
Molarity = moles of solute/Liters of solution ( 50.0 ml = 0.05 Liters ) 0.552 M KCl = moles/.0.05 liters = 0.0276 moles of KCl
Molarity = moles of solute/Liters of solution ( 22.0 ml = 0.022 Liters ) moles of solute = Molarity * Liters of solution Moles of NaCl = 0.500 M * 0.022 Liters = 0.011 moles of sodium chloride -------------------------------------------
The Stoichiometry of molar concentration follows this simple formula: Mol = Volume (dm³) × Molar Concentration (mol/dm³) Hence: Molar Concentration (mol/dm³) = Number of moles (mol)/ Volume (dm³)
The answer is 0,0509 mole.
5.50eq noob
Molarity = moles of solute/Liters of solution ( 20.0 ml = 0.02 Liters ) moles of solute = Liters of solution * Molarity 0.02 Liters * 0.800 M MgCl2 = 0.016 moles MgCl2 -------------------------------
This mass is 347,67 for KMnO4.