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# How many moles of MgCl2 are present in 20.0 mL of 0.800 M MgCl2 solution?

Updated: 1/27/2024

Wiki User

12y ago

To find the number of moles of MgCl2, you can use the formula:

Moles

=

Molarity

×

Volume (in liters)

Moles=Molarity×Volume (in liters)

Given that the molarity (

M

M) is

0.800

mol/L

0.800mol/L and the volume is

20.0

mL

20.0mL, you first need to convert the volume to liters by dividing it by

1000

1000 (since

1

L

=

1000

mL

1L=1000mL):

Volume (in liters)

=

20.0

mL

1000

Volume (in liters)=

1000

20.0mL

Volume (in liters)

=

0.020

L

Volume (in liters)=0.020L

Now, use the formula to calculate the moles:

Moles

=

0.800

mol/L

×

0.020

L

Moles=0.800mol/L×0.020L

Moles

=

0.016

mol

Moles=0.016mol

Therefore, there are

0.016

moles

0.016moles of MgCl2 present in

20.0

mL

20.0mL of a

0.800

M

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Surveytoriches

Lvl 5
1mo ago

Wiki User

12y ago

Molarity = moles of solute/Liters of solution ( 20.0 ml = 0.02 Liters )

moles of solute = Liters of solution * Molarity

0.02 Liters * 0.800 M MgCl2

= 0.016 moles MgCl2

-------------------------------

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