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How many moles of sodium chhloride are present in 22.0 ml of 0.500 m solution?
Wiki User
∙ 12y ago
Molarity = moles of solute/Liters of solution ( 22.0 ml = 0.022 Liters )
moles of solute = Molarity * Liters of solution
Moles of NaCl = 0.500 M * 0.022 Liters
= 0.011 moles of sodium chloride
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Wiki User
∙ 12y ago
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