Molarity = moles of solute/Liters of solution ( find the moles )
2.36 M NaCl = moles NaCl/5.08 Liters NaCl
= 12.0 moles
200/1000 x 6 = 1.2 moles
Molarity = moles of solute/Liters of solution ( 22.0 ml = 0.022 Liters ) moles of solute = Molarity * Liters of solution Moles of NaCl = 0.500 M * 0.022 Liters = 0.011 moles of sodium chloride -------------------------------------------
There are two moles of sodium ions in two moles of sodium chloride.
Every formula unit of sodium chloride has one sodium atom. Therefore, there are 4.0 moles of sodium ions in 4.0 moles of NaCl.
The formula mass of sodium chloride is 58.5 Amount of NaCl = 22.6/58.5 = 0.386mol
This solution contain 0,3 mol of sodium chloride.
The answer is 2,4 moles.
200/1000 x 6 = 1.2 moles
0,40 moles of sodium chloride contain 23,376 g.
0.1 Moles
2.27
Molarity = moles of solute/Liters of solution ( 22.0 ml = 0.022 Liters ) moles of solute = Molarity * Liters of solution Moles of NaCl = 0.500 M * 0.022 Liters = 0.011 moles of sodium chloride -------------------------------------------
The answer is 0,175 moles.
There are 10 moles present in 585 g of sodium chloride.
23.3772 grams are there in four tenths moles of sodium chloride
3.6
This depends on the concentration of sodium chloride in water.