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What can make 20 moles of sodium chloride?

To make 20 moles of sodium chloride, you would need 20 moles of sodium ions and 20 moles of chloride ions. This could be achieved by combining 40 moles of sodium atoms with 40 moles of chlorine atoms to form 20 moles of sodium chloride.


Calculate the mass of solid needed to make the solution 100 ml of solution that is 1.0 M in sodium cation using sodium chloride?

To make a 1.0 M solution of sodium cation using sodium chloride, you need to consider the molar mass of sodium chloride (58.44 g/mol). Since 1 mole of sodium chloride provides 1 mole of sodium cation, you would need 58.44 g of sodium chloride to make a 1.0 M solution in 100 ml.


How many grams of sodium chloride are required to make a 1.0 L solution with a concentration of 3.5 M?

The molecular weight of NaCl is 58.44; sodium =22.99; Chlorine=35.45. A 1 molar solution is the molecular weight in grams in 1 litre of water, so a 3.5 molar solution would be 58.44g multiplied by 3.5, which is 204.54g in 1L.


What gram of sodium chloride is required to make 500ppm of sodium chloride?

It depends on the volume, if we consider 1 liter of the solution 500 mg of sodium chloride is needed.


How many grams of sodium chloride would you need to make a 5.0m salt solution?

The sodium chloride mass needed is 292,2 g


What is the molarity when water is added to 2 moles of sodium chloride to make 0.5 liter of solution?

Molarity is calculated as moles of solute divided by volume of solution in liters. In this case, you have 2 moles of sodium chloride in a 0.5 liter solution. So the molarity would be 2 moles / 0.5 L = 4 M.


How many grams of sodium metal are needed to make 29.3 grams of sodium chloride?

Since sodium chloride has equal parts of sodium and chlorine by weight, you would need 29.3 grams of sodium to create 29.3 grams of sodium chloride.


How much sodium chloride in grams is needed to make 13 L of a solution that has a concentration of 4 grams of sodium chloride per liter of solution?

To calculate the total amount of sodium chloride needed for a 13 L solution at 4 grams per liter, multiply the concentration by the volume of the solution: 4 grams/L x 13 L = 52 grams of sodium chloride. Therefore, you will need 52 grams of sodium chloride to make the 13 L solution.


How many grams of sodium chloride does it take to make 1.00 L of a 0.5 M solution?

The needed mass of sodium chloride is 29,22 g.


Can sodium chloride be used to make soap instead of lye?

No, sodium chloride (table salt) cannot be used to make soap instead of lye. Lye (sodium hydroxide or potassium hydroxide) is the essential ingredient needed to saponify fats and oils to make soap. Sodium chloride does not have the same chemical properties to facilitate the soap-making process.


How many grams of sodium chloride is obtained by the action of chlorine with 4 moles sodium?

A mole of an element or compound is 6.022 x 1023 (Avogadro's constant) molecules of that substance. This number is the number of molecules it takes for an amount of substance to have a mass in grams the same as its molecular mass: carbon has a molecular mass of 12, so 6.022 x 1023 (one mole) carbon atoms have a mass of 12 grams. The molecular mass of sodium is 23 (22.989) so one mole of sodium has a mass of 23 grams. Sodium chloride has a molecular mass of 58.44 so a mole of NaCl is 58.44 grams. One mole of sodium will make one mole of sodium chloride. Na + Cl => NaCl So four moles of sodium will make four moles of sodium chloride. 4Na + 4Cl => 4NaCl Four moles of NaCl has a mass of 4 x 58.44 = 233.76 grams.


How many grams of chlorine are needed to combine with 23g of sodium to make 58.5g of sodium chloride?

To determine the grams of chlorine needed to combine with 23g of sodium to make 58.5g of sodium chloride (NaCl), we start by noting that NaCl consists of sodium (Na) and chlorine (Cl) in a 1:1 molar ratio. Given that 23g of sodium is present, the total mass of sodium chloride includes the sodium plus the mass of chlorine. Therefore, the mass of chlorine required is 58.5g (total NaCl) - 23g (sodium) = 35.5g of chlorine.