3.6
A mole of an element or compound is 6.022 x 1023 (Avogadro's constant) molecules of that substance. This number is the number of molecules it takes for an amount of substance to have a mass in grams the same as its molecular mass: carbon has a molecular mass of 12, so 6.022 x 1023 (one mole) carbon atoms have a mass of 12 grams. The molecular mass of sodium is 23 (22.989) so one mole of sodium has a mass of 23 grams. Sodium chloride has a molecular mass of 58.44 so a mole of NaCl is 58.44 grams. One mole of sodium will make one mole of sodium chloride. Na + Cl => NaCl So four moles of sodium will make four moles of sodium chloride. 4Na + 4Cl => 4NaCl Four moles of NaCl has a mass of 4 x 58.44 = 233.76 grams.
It depends on what you are reacting the sodium with to generate hydrogen gas. The question is incomplete and cannot be answered as it is written
Sodium sulfate is not prepared from hydrogen chloride.
sodium chloride<----- this is wrong im sorry the right answer is Nitrates is totaly awfull
The volume is 0,3 mL.
To make 20 moles of sodium chloride, you would need 20 moles of sodium ions and 20 moles of chloride ions. This could be achieved by combining 40 moles of sodium atoms with 40 moles of chlorine atoms to form 20 moles of sodium chloride.
To make a 1.0 M solution of sodium cation using sodium chloride, you need to consider the molar mass of sodium chloride (58.44 g/mol). Since 1 mole of sodium chloride provides 1 mole of sodium cation, you would need 58.44 g of sodium chloride to make a 1.0 M solution in 100 ml.
The molecular weight of NaCl is 58.44; sodium =22.99; Chlorine=35.45. A 1 molar solution is the molecular weight in grams in 1 litre of water, so a 3.5 molar solution would be 58.44g multiplied by 3.5, which is 204.54g in 1L.
It depends on the volume, if we consider 1 liter of the solution 500 mg of sodium chloride is needed.
The sodium chloride mass needed is 292,2 g
Molarity is calculated as moles of solute divided by volume of solution in liters. In this case, you have 2 moles of sodium chloride in a 0.5 liter solution. So the molarity would be 2 moles / 0.5 L = 4 M.
Since sodium chloride has equal parts of sodium and chlorine by weight, you would need 29.3 grams of sodium to create 29.3 grams of sodium chloride.
To calculate the total amount of sodium chloride needed for a 13 L solution at 4 grams per liter, multiply the concentration by the volume of the solution: 4 grams/L x 13 L = 52 grams of sodium chloride. Therefore, you will need 52 grams of sodium chloride to make the 13 L solution.
The needed mass of sodium chloride is 29,22 g.
No, sodium chloride (table salt) cannot be used to make soap instead of lye. Lye (sodium hydroxide or potassium hydroxide) is the essential ingredient needed to saponify fats and oils to make soap. Sodium chloride does not have the same chemical properties to facilitate the soap-making process.
A mole of an element or compound is 6.022 x 1023 (Avogadro's constant) molecules of that substance. This number is the number of molecules it takes for an amount of substance to have a mass in grams the same as its molecular mass: carbon has a molecular mass of 12, so 6.022 x 1023 (one mole) carbon atoms have a mass of 12 grams. The molecular mass of sodium is 23 (22.989) so one mole of sodium has a mass of 23 grams. Sodium chloride has a molecular mass of 58.44 so a mole of NaCl is 58.44 grams. One mole of sodium will make one mole of sodium chloride. Na + Cl => NaCl So four moles of sodium will make four moles of sodium chloride. 4Na + 4Cl => 4NaCl Four moles of NaCl has a mass of 4 x 58.44 = 233.76 grams.
To determine the grams of chlorine needed to combine with 23g of sodium to make 58.5g of sodium chloride (NaCl), we start by noting that NaCl consists of sodium (Na) and chlorine (Cl) in a 1:1 molar ratio. Given that 23g of sodium is present, the total mass of sodium chloride includes the sodium plus the mass of chlorine. Therefore, the mass of chlorine required is 58.5g (total NaCl) - 23g (sodium) = 35.5g of chlorine.