It depends on what you are reacting the sodium with to generate hydrogen gas. The question is incomplete and cannot be answered as it is written
You can make a simple balance. There are (12.36 * 3) moles of H You have 2*H to form H2. So take the total from ammonia and divide by two to find the moles of H2 required.
H2 +Cl2---------------->2HCl Since H2 and Cl2 react in 1:1 mole ratio the number of moles of H2 reacting is equal to the number of moles of Cl2 which is equal to 0.213
11 g hydrogen are needed.
Al+HCl===> AlCl3+H2 Is the reaction. You need &.2 moles of HCl.
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You can make a simple balance. There are (12.36 * 3) moles of H You have 2*H to form H2. So take the total from ammonia and divide by two to find the moles of H2 required.
H2 +Cl2---------------->2HCl Since H2 and Cl2 react in 1:1 mole ratio the number of moles of H2 reacting is equal to the number of moles of Cl2 which is equal to 0.213
N2 + 3H2 -> 2NH3 If you have moles produced you can do it this way. 22.5 moles NH3 (3 moles H2/2 moles NH3) = 33.8 moles H2 needed -----------------------------------
11 g hydrogen are needed.
2H2 + O2 --> 2H2OFor every 2 moles of H2, 2 moles of H2O will be produced (i.e., a 1:1 ratio). So to produce 8.25 moles of H2O you will also need 8.25 moles of H2
Al+HCl===> AlCl3+H2 Is the reaction. You need &.2 moles of HCl.
To find the grams of H2 needed, we first calculate the moles of NH3 using its molar mass. Then, we use the balanced chemical equation to determine the mole ratio of H2 to NH3. Finally, we convert moles of H2 to grams using its molar mass.
Assuming a balanced chemical equation, you would need 3 moles of H2 to react with 1 mole of N2. Therefore, if you have 0.90 moles of N2, you would need 0.90 x 3 = 2.70 moles of H2 to fully react with it.
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Balanced equation. N2 + 3H2 --> 2NH3 1.4 moles H2 (2 moles NH3/3 moles H2) = 0.93 moles NH3 produced =======================
I assume you mean this reaction. Zn + 2HCl --> ZnCl2 + H2 2.3 moles zinc (2 moles HCl/1 mole Zn) = 4.6 moles hydrochloric acid needed ========================
To calculate the mass of H2 needed to produce 13.14g of NH3, you can use the molar ratio between H2 and NH3. From the balanced chemical equation for the reaction, you can see that 2 moles of NH3 are produced for every 3 moles of H2 consumed. First, calculate the number of moles of NH3 using its molar mass, then use the molar ratio to find the moles of H2 needed, and finally convert the moles of H2 into grams.