I assume you mean this reaction.
N2 + 3H2 --> 2NH3
0.90 moles N2 (3 moles H2/1 mole N2)
= 2.7 moles hydrogen gas needed
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How many moles of C are needed to react with 0.490 mole SO2?
Since molecules of potassium contain only single potassium atoms, molecules of iodine contain two atoms, and moles of potassium iodide contain one atom of each element, 2.5 moles of iodine are needed to react completely with 5 moles of potassium.
4 mole cuO X 2/1 = 8 mole Hcl
The balanced equation for the reaction is: 3H2 + N2 -> 2NH3 From the balanced equation, we can see that 3 moles of hydrogen are needed to react completely with 1 mole of nitrogen. So if there are 3 moles of nitrogen, you would need 9 moles of hydrogen to react completely.
To determine the number of moles of calcium hydroxide needed to react with the nitric acid, you would need to know the concentration of the nitric acid. With the concentration, you can use the balanced chemical equation of the reaction to calculate the moles of calcium hydroxide required.
10 moles of nitrogen dioxide are needed to react with 5,0 moles of water.
How many moles of C are needed to react with 0.490 mole SO2?
Since molecules of potassium contain only single potassium atoms, molecules of iodine contain two atoms, and moles of potassium iodide contain one atom of each element, 2.5 moles of iodine are needed to react completely with 5 moles of potassium.
The answer is 699 moles perchloric acid.
These reagents doesn't react.
1.35
63 g of water are needed.
4 mole cuO X 2/1 = 8 mole Hcl
The balanced equation for the reaction is: 3H2 + N2 -> 2NH3 From the balanced equation, we can see that 3 moles of hydrogen are needed to react completely with 1 mole of nitrogen. So if there are 3 moles of nitrogen, you would need 9 moles of hydrogen to react completely.
The balanced chemical equation for the reaction between sodium and water is: 2 Na + 2 H2O -> 2 NaOH + H2 Since 2 moles of water are needed to react with 2 moles of sodium, 1 mole of water is needed to react with 1 mole of sodium. Therefore, 2.5 moles of sodium will require 2.5 moles of water for the reaction.
Al+HCl===> AlCl3+H2 Is the reaction. You need &.2 moles of HCl.
H2 +Cl2---------------->2HCl Since H2 and Cl2 react in 1:1 mole ratio the number of moles of H2 reacting is equal to the number of moles of Cl2 which is equal to 0.213