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How many moles of oxygen are needed to burn 7.0 mols of phosphorus?
8,75 moles of oxygen are needed.
If 4 moles of hydrogen is completely oxidized with oxygen how many moles of oxygen will be consumed?
0. Hydrogen doesn't "reackt" to form Nitrogen Monoxide.
How many moles of O2 are needed to burn 1.35mol of C8H18?
16,875 moles of oxygen are needed.
How many moles of Cl- ions are needed to completely combine with 0.25 moles of Mg plus 2ions?
0,5 moles Cl-
How many moles of oxygen would be needed for the complete combustion of the 3 moles of the hydrogen?
1 mole
How many moles of oxygen are needed to burn 7.0 mols of phosphorus?
8,75 moles of oxygen are needed.
How many moles of oxygen are needed to completely react with 6 moles of hydrogen?
The balanced chemical equation for the reaction between hydrogen and oxygen is: 2H2 + O2 -> 2H2O This equation shows that 1 mole of O2 reacts with 2 moles of H2. So, to completely react with 6 moles of H2, you would need 3 moles of O2.
If 4 moles of hydrogen is completely oxidized with oxygen how many moles of oxygen will be consumed?
0. Hydrogen doesn't "reackt" to form Nitrogen Monoxide.
How many moles of O2 are needed to burn 1.35mol of C8H18?
16,875 moles of oxygen are needed.
How many moles of oxygen are needed to react completely with 2.3 moles of H2S?
The balanced chemical equation for the reaction between oxygen (O2) and hydrogen sulfide (H2S) is: 2H2S + 3O2 -> 2SO2 + 2H2O From the equation, it is a 3:2 ratio of O2 to H2S. Therefore, if 2.3 moles of H2S are present, (2.3 moles H2S) * (3 moles O2 / 2 moles H2S) = 3.45 moles of O2 are needed.
How many moles of oxygen are necessary to react completely with 4 moles of propane?
For the reaction of propane (C3H8) with oxygen (O2), the balanced equation is: C3H8 + 5O2 -> 3CO2 + 4H2O. This means that 5 moles of O2 are required to react completely with 1 mole of propane (C3H8). Therefore, to react completely with 4 moles of propane, you would need 20 moles of O2.
How many moles of Cl- ions are needed to completely combine with 0.25 moles of Mg plus 2ions?
0,5 moles Cl-
How many grams of oxygen are needed to react completely with 200.0 g of ammonia NH3?
The balanced chemical equation for the reaction between ammonia (NH3) and oxygen (O2) is 4NH3 + 3O2 → 2N2 + 6H2O. From the equation, we can see that 3 moles of O2 are needed to react with 4 moles of NH3. This means the molar ratio of O2 to NH3 is 3:4. First, calculate the number of moles of NH3 in 200.0 g: 200.0 g NH3 / 17.03 g/mol NH3 = 11.75 moles NH3 Now, calculate the number of moles of O2 needed using the molar ratio: 11.75 moles NH3 * (3 moles O2 / 4 moles NH3) = 8.81 moles O2 Finally, convert moles of O2 to grams: 8.81 moles O2 * 32 g/mol O2 = 282.0 g O2.
How many moles of oxygen are needed to react completely with 2.3 moles of H2S 2H2S plus 3O2 2SO2 plus 2H2O?
The balanced equation shows that 2 moles of H2S react with 3 moles of O2. Therefore, to react completely with 2.3 moles of H2S, you would need (3/2) x 2.3 moles of O2 which is equal to 3.45 moles of O2.
How many moles of oxygen would be needed for the complete combustion of the 3 moles of the hydrogen?
1 mole
How many moles of oxygen gas are needed to make 4 moles of water?
4 moles of oxygen atoms are present in 4 moles of H2O
How many grams of 02(g) are needed to completely burn 23.7 g of C38H(g)?
The balanced equation is C3H8 + 5O2 ---> 3CO2 + 4H2O moles C3H8 = 23.7 g x 1 mol/44 g = 0.539 moles moles O2 needed = 5 x 0.539 moles = 2.695 moles O2 (it takes 5 moles O2 per mole C3H8) grams O2 needed = 2.695 moles x 32 g/mole = 86.2 grams O2 needed (3 sig figs)
