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How many grams of ccl4 are needed to have 5.000 mol?
To find the grams of CCl4 needed, multiply the number of moles (5.000 mol) by the molar mass of CCl4 (153.82 g/mol). (5.000 , \text{mol} \times 153.82 , \text{g/mol} = 769.1 , \text{g}) Therefore, 769.1 grams of CCl4 are needed.
How many grams of KO2 are needed to form 8.5 grams of O2?
You would need 18 grams to get the requirement. Using a chemical equation can help to solve this for you.
How many calories would be needed to melt 10 grams of ice at 0 degrees C?
To melt 10 grams of ice at 0 degrees Celsius, it would require 80 calories of heat energy per gram, so a total of 800 calories (80 calories/gram * 10 grams = 800 calories) would be needed.
How many grams in announce?
How many grams are in an ounce
How many grams of H 2O will be produced if 750 grams of Fe are produced?
In the reaction of Fe with H₂O to produce FeO and H₂, the ratio is 3 moles of H₂O for every 1 mole of Fe. Since the molar mass of Fe is 56 g/mol and that of H₂O is 18 g/mol, we use these values to find that 750 grams of Fe will produce 750 * (3 * 18 / 56) = 857.14 grams of H₂O.
How many grams of chloral are needed to produce 10.5 g DDT?
To produce 1 gram of DDT, 3.3 grams of chloral are needed. Therefore, to produce 10.5 grams of DDT, you would need 10.5 * 3.3 = 34.65 grams of chloral.
How many grams of water are needed to produce one hundred fifty grams of magnesium hydroxide?
A lot
How many grams of carbon dioxide are needed to produce 125 grams of urea?
To produce 1 mole of urea, 1 mole of carbon dioxide is needed. The molar mass of urea is 60 grams/mol, and the molar mass of carbon dioxide is 44 grams/mol. Therefore, to produce 125 grams of urea, 125 grams/60 grams/mol = 2.08 moles of urea is needed. This means 2.08 moles of carbon dioxide is needed, which is 2.08 moles * 44 grams/mol = 91.52 grams of carbon dioxide needed.
How many grams of oxygen will be required to produce 25 moles of sulfur dioxide how many grams of oxygen will be required to produce 25 moles of sulfur dioxide?
800 g oxygen are needed.
How many grams of potassium iodide will produce 750 grams of silver iodide when there is an excess of silver nitrate?
530,3 g potassium iodide are needed.
How many grams of oxygen are needed to react with 350 grams of iron to produce 500 grams of fe203?
The balanced chemical equation for the reaction between iron and oxygen to produce Fe2O3 is 4Fe + 3O2 -> 2Fe2O3. From the equation, we see that 3 moles of oxygen react with 4 moles of iron to produce 2 moles of Fe2O3. Therefore, to find the grams of oxygen needed, we need to calculate the molar mass of Fe2O3 and then determine the number of grams needed using the mole ratio from the balanced equation.
If 350 grams is needed for 10000 liters how many grams is needed for 3300 liters?
To solve this, we will figure out how many grams there are per litre. To do this, we will divide the overall amount of litres 350 grams goes into by 350, so we are dividing 350 by 10,000. This answer is 0.035. We will then multiply 0.035 (how many grams needed for one litre) by 3300, to get how many are needed for that many litres, which gives us 115.5 grams. 115.5 grams are needed for 3300 litres if 250 grams are needed for 10,000 litres.
How many grams of ammonia NH3 will produce 300 grams of N2?
394.794 grams
How many grams of H2SO4 will 200 grams of SO3 and 100 grams of H2O produce?
About 245 grams.
How many grams of chlorine are needed to produce 1.5 mole chloroform?
To produce 1 mole of chloroform, you need 3 moles of chlorine. So, to produce 1.5 moles of chloroform, you would need 4.5 moles of chlorine. Converting moles to grams by using the molar mass of chlorine (35.5 g/mol) gives you 160.5 grams of chlorine required.
How many grams of aluminum is required to produce 25.0 grams of aluminum sulfate?
To find the amount of aluminum needed to produce aluminum sulfate, you need to consider the molar mass of aluminum sulfate and the ratio of aluminum in the compound. First, calculate the molar mass of aluminum sulfate (Al2(SO4)3). Then, find the ratio of aluminum in the compound (2 moles of Al in 1 mole of Al2(SO4)3). Finally, use this information to calculate the grams of aluminum needed to produce 25.0 grams of aluminum sulfate.
How many grams of H2 are needed to produce 14.84 g of NH3?
To find the grams of H2 needed, we first calculate the moles of NH3 using its molar mass. Then, we use the balanced chemical equation to determine the mole ratio of H2 to NH3. Finally, we convert moles of H2 to grams using its molar mass.
