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How many grams of oxygen are needed to react with 350 grams of iron to produce 500 grams of fe203?
The balanced chemical equation for the reaction between iron and oxygen to produce Fe2O3 is 4Fe + 3O2 -> 2Fe2O3. From the equation, we see that 3 moles of oxygen react with 4 moles of iron to produce 2 moles of Fe2O3. Therefore, to find the grams of oxygen needed, we need to calculate the molar mass of Fe2O3 and then determine the number of grams needed using the mole ratio from the balanced equation.
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How many grams of potassium chlorate will produce 112.5g of oxygen?
To calculate the amount of potassium chlorate needed to produce 112.5g of oxygen, you first need to determine the molar ratio between potassium chlorate and oxygen. Then, use this ratio to convert the grams of oxygen to grams of potassium chlorate using the molar masses of each compound.
When 31 grams of phosphorous reacts with oxygen 71 grams of an oxide phosphorus is the product. What mass of oxygen is needed to produce 13 grams of this product?
To find the mass of oxygen needed to produce 13 grams of the oxide, we first find the molar ratio between P and O in the product. Then, use this ratio to calculate the mass of oxygen needed. Since 71g of the oxide contains 31g of phosphorus, we can calculate the mass of oxygen needed for 13g of the oxide by setting up a proportion.
How many grams of mercury II oxide are needed to produce 1.56 L of oxygen gas according to the following reaction at 25C and 1 ATM?
You would need 5.7 grams of mercury II oxide to produce 1.56 L of oxygen gas according to the following reaction at those conditions.
How many grams of carbon dioxide are needed to produce 125 grams of urea?
To produce 1 mole of urea, 1 mole of carbon dioxide is needed. The molar mass of urea is 60 grams/mol, and the molar mass of carbon dioxide is 44 grams/mol. Therefore, to produce 125 grams of urea, 125 grams/60 grams/mol = 2.08 moles of urea is needed. This means 2.08 moles of carbon dioxide is needed, which is 2.08 moles * 44 grams/mol = 91.52 grams of carbon dioxide needed.
How many grams of oxygen are needed to produce 95.6 g of aluminum oxide?
To find the amount of oxygen needed to produce 95.6 g of aluminum oxide (Al2O3), first calculate the molar mass of Al2O3 (101.96 g/mol). Then, set up a ratio using the molar mass ratio of oxygen to Al2O3 (3:2). Calculate the amount of oxygen needed using the given mass of Al2O3 and the molar ratio.
How many grams of oxygen will be required to produce 25 moles of sulfur dioxide how many grams of oxygen will be required to produce 25 moles of sulfur dioxide?
800 g oxygen are needed.
How many grams of potassium chlorate will produce 112.5g of oxygen?
To calculate the amount of potassium chlorate needed to produce 112.5g of oxygen, you first need to determine the molar ratio between potassium chlorate and oxygen. Then, use this ratio to convert the grams of oxygen to grams of potassium chlorate using the molar masses of each compound.
When 31 grams of phosphorous reacts with oxygen 71 grams of an oxide phosphorus is the product. What mass of oxygen is needed to produce 13 grams of this product?
To find the mass of oxygen needed to produce 13 grams of the oxide, we first find the molar ratio between P and O in the product. Then, use this ratio to calculate the mass of oxygen needed. Since 71g of the oxide contains 31g of phosphorus, we can calculate the mass of oxygen needed for 13g of the oxide by setting up a proportion.
How many grams of chloral are needed to produce 10.5 g DDT?
To produce 1 gram of DDT, 3.3 grams of chloral are needed. Therefore, to produce 10.5 grams of DDT, you would need 10.5 * 3.3 = 34.65 grams of chloral.
what is the mass in grams of oxygen, is needed to complete combustion of 6 L of methane?
what is the mass in grams of oxygen, is needed to complete combustion of 6 L of methane?
How many grams of mercury II oxide are needed to produce 1.56 L of oxygen gas according to the following reaction at 25C and 1 ATM?
You would need 5.7 grams of mercury II oxide to produce 1.56 L of oxygen gas according to the following reaction at those conditions.
How many grams of carbon dioxide are needed to produce 125 grams of urea?
To produce 1 mole of urea, 1 mole of carbon dioxide is needed. The molar mass of urea is 60 grams/mol, and the molar mass of carbon dioxide is 44 grams/mol. Therefore, to produce 125 grams of urea, 125 grams/60 grams/mol = 2.08 moles of urea is needed. This means 2.08 moles of carbon dioxide is needed, which is 2.08 moles * 44 grams/mol = 91.52 grams of carbon dioxide needed.
How many grams of oxygen are needed to produce 95.6 g of aluminum oxide?
To find the amount of oxygen needed to produce 95.6 g of aluminum oxide (Al2O3), first calculate the molar mass of Al2O3 (101.96 g/mol). Then, set up a ratio using the molar mass ratio of oxygen to Al2O3 (3:2). Calculate the amount of oxygen needed using the given mass of Al2O3 and the molar ratio.
How many grams of oxygen are need to react with 4.6 grams of titanium chloride?
To find the grams of oxygen needed, we first calculate the molar mass of titanium chloride (TiCl4) and oxygen (O2). Then, we use the molar ratio of TiCl4 to O2 from the balanced chemical equation to find the grams of O2 needed.
How many grams of oxygen are needed to react with 23.9 grams of ammonia?
The balanced equation for the reaction between ammonia (NH3) and oxygen (O2) is 4NH3 + 5O2 → 4NO + 6H2O. To find the grams of oxygen needed to react with 23.9 grams of ammonia, you need to calculate the molar ratio between ammonia and oxygen using the balanced equation. Once you find the molar ratio, you can calculate the grams of oxygen required.
How many grams of hydrogen must be added to 800 grams of oxygen to produce 900 grams of water?
For the reaction 2H₂ + O₂ → 2H₂O, we know that the molar ratio of H₂ to O₂ is 2:1. To produce 900 grams of water, we need 450 grams of hydrogen (900g / 2). Therefore, we need to add 450 grams of hydrogen to 800 grams of oxygen to produce 900 grams of water.
What amount of oxygen is needed to produce 12000 mols of nitrogen monoxide gas?
As oxygen is a diatomic gas it would take 6000 moles. As oxygen gas is 32 g/mole this would be 192000 grams or 192kg. At STP this would be a volume of (1)V =6000R(273) P=1atm R=8.314 v=13,618,332m3
