As oxygen is a diatomic gas it would take 6000 moles.
As oxygen gas is 32 g/mole this would be 192000 grams or 192kg.
At STP this would be a volume of (1)V =6000R(273)
P=1atm
R=8.314
v=13,618,332m3
To produce 100.0 kg of methanol, you would need 50.0 kg of carbon monoxide and 150.0 kg of hydrogen. This is because the reaction to produce methanol from carbon monoxide and hydrogen has a 1:3 ratio.
A high voltage spark is needed to produce nitrogen dioxide by causing a reaction between nitrogen and oxygen in the air. This reaction forms highly reactive nitric oxide ions, which then combine with more oxygen to form nitrogen dioxide. The energy from the spark helps drive the reaction forward by providing the activation energy needed for these reactions to occur.
The balanced equation for the reaction is: 3H2 + N2 -> 2NH3 From the balanced equation, we can see that 3 moles of hydrogen are needed to react completely with 1 mole of nitrogen. So if there are 3 moles of nitrogen, you would need 9 moles of hydrogen to react completely.
Nitrogen is a key component of amino acids, which are the building blocks of proteins necessary for growth and repair in living organisms. Nitrogen is also essential for the synthesis of nucleic acids, such as DNA and RNA, which carry genetic information. Additionally, nitrogen is a vital component of chlorophyll, the molecule that allows plants to photosynthesize and produce their own food.
That amount of ammonia contains two moles of hydrogen gas. One mole of hydrogen gas weighs 2.016 grams. Therfore 3.75 grams of ammonia contains two moles of hydrogen.
To find the grams of nitrogen dioxide needed, first calculate the moles of nitrogen monoxide using Avogadro's number. Then, use the balanced chemical equation to determine the moles of nitrogen dioxide required. Finally, convert moles to grams using the molar mass of nitrogen dioxide.
To produce 5.00x10^22 molecules of nitrogen monoxide (NO), you need an equal number of molecules of nitrogen dioxide (NO2). With the balanced chemical equation 2NO2 + H2O → 2NO + 2HNO3, you can calculate the mass of nitrogen dioxide needed using the molar masses of NO2 and NO.
The reaction to form nitrogen dioxide using nitric oxide is; 2NO(g) + O2(g) -> 2NO2(g) As the stoichiometry between the substances are 1:1, 1.35 moles of nitrogen monoxide is needed.
To produce 100.0 kg of methanol, you would need 50.0 kg of carbon monoxide and 150.0 kg of hydrogen. This is because the reaction to produce methanol from carbon monoxide and hydrogen has a 1:3 ratio.
The minimum amount of unstable atoms needed to produce an uncontrolled chain reaction is called?
16,45 g nitrogen are needed.
No. It is not needed. Carbon monoxide is a common by-product of burning carbon or carbon-containing compounds.
Yes, nitrogen is an essential nutrient needed by plants to make proteins. Plants absorb nitrogen from the soil in the form of nitrates or ammonium ions, which are then used in the process of protein synthesis. Without nitrogen, plants would not be able to produce the proteins necessary for their growth and development.
A high voltage spark is needed to produce nitrogen dioxide by causing a reaction between nitrogen and oxygen in the air. This reaction forms highly reactive nitric oxide ions, which then combine with more oxygen to form nitrogen dioxide. The energy from the spark helps drive the reaction forward by providing the activation energy needed for these reactions to occur.
A forty pound (40) bag is the amount of 25 percent nitrogen fertilizer needed for a 970 square foot bed.Specifically, calculate the amount of 25 percent nitrogen needed for a 1,000 square foot bed. Convert the 25 percent by multiplying it by 100 to get 4. Then divide 4 by 1,000 square feet to get 38.8 pounds.
The minimum amount of unstable atoms needed to produce an uncontrolled chain reaction is called critical mass.
Each mole of ammonia requires one mole of nitrogen atoms. However, the nitrogen in the air occurs as diatomic molecules; therefore, only one-half mole of molecular nitrogen is required for each mole of ammonia.