1 mole of carbon monoxide and 2 moles of diatomic hydrogen.
methanol density is 0.739kg/L mass of methanol is =739g molarity of methanol is = 793*1000/(32.043*1000) that is (M1)=24.75mol/L V1=(M2*V2)/M1 V1 = 2.5*0.25/24.75 V1 = 0.25L so, 0.25L volume needed for making 2.5L of methanol 0.25Msolution
To prepare a 0.1 molar methanolic HCl solution, you would first calculate the amount of hydrochloric acid needed to achieve a concentration of 0.1 moles in 1 liter of methanol. You would then measure out the calculated amount of hydrochloric acid and add it to the methanol in a volumetric flask. Finally, you would top up the flask with methanol to make a final volume of 1 liter and mix well.
Baking soda
To prepare a 2.5 N NaOH solution in methanol, you would first calculate the amount of NaOH needed based on its molar mass and the desired concentration. Then, dissolve this amount of NaOH in the appropriate volume of methanol to make the 2.5 N solution. Be sure to wear appropriate safety gear and follow proper handling procedures when working with NaOH.
To answer this question, we need additional information about the reactants involved in the reaction. If the reaction is the stoichiometric reaction between hydrogen gas (H₂) and another reactant, we would need the balanced chemical equation to determine the mole ratio between H₂ and the other reactant. Once we have this information, we can calculate the moles of H₂ needed based on the given amount of the other reactant.
No. Alkoxide ions are stronger bases than hydroxide ions. The only way of making an alkoxide is by reacting a hihgly reactive metal such as sodium with the corresponding alcohol (react sodium with methanol to produce sodium methoxide). In water sodium methoxide will react to produce sodium hydroxide and methanol.
The technology needed for the project, and what benefits that technology would produce
methanol density is 0.739kg/L mass of methanol is =739g molarity of methanol is = 793*1000/(32.043*1000) that is (M1)=24.75mol/L V1=(M2*V2)/M1 V1 = 2.5*0.25/24.75 V1 = 0.25L so, 0.25L volume needed for making 2.5L of methanol 0.25Msolution
To make a 100 ppm solution of methanol in 100 mL of water, you would need 10 mg of methanol. This is because 100 ppm is equivalent to 100 mg/L, and since you have 100 mL of water, you would need 10 mg of methanol (100 mg/L x 0.1 L).
B would likely be a reactant in the chemical reaction, as it is being completely used up to produce the products of the reaction. It is considered a limiting reactant in this case.
To prepare a 0.1 molar methanolic HCl solution, you would first calculate the amount of hydrochloric acid needed to achieve a concentration of 0.1 moles in 1 liter of methanol. You would then measure out the calculated amount of hydrochloric acid and add it to the methanol in a volumetric flask. Finally, you would top up the flask with methanol to make a final volume of 1 liter and mix well.
CO2 + H2 -> CO + H2O one to one here 30.6 moles H2O (1 mole H2/1 mole H2O) = 30.6 moles Hydrogen gas needed
To prepare a 10 ppm (parts per million) calibration gas in 100 mL of nitrogen, you need to calculate the amount of methanol required. Since 10 ppm means 10 mg of methanol per liter of gas, for 100 mL (0.1 L), you would need 1 mg of methanol. To achieve this, you can directly weigh out 1 mg of methanol and dilute it in the 100 mL of nitrogen.
Baking soda
To prepare a 2.5 N NaOH solution in methanol, you would first calculate the amount of NaOH needed based on its molar mass and the desired concentration. Then, dissolve this amount of NaOH in the appropriate volume of methanol to make the 2.5 N solution. Be sure to wear appropriate safety gear and follow proper handling procedures when working with NaOH.
To answer this question, we need additional information about the reactants involved in the reaction. If the reaction is the stoichiometric reaction between hydrogen gas (H₂) and another reactant, we would need the balanced chemical equation to determine the mole ratio between H₂ and the other reactant. Once we have this information, we can calculate the moles of H₂ needed based on the given amount of the other reactant.
One Newton would be needed.