methanol density is 0.739kg/L
mass of methanol is =739g
molarity of methanol is = 793*1000/(32.043*1000)
that is (M1)=24.75mol/L
V1=(M2*V2)/M1
V1 = 2.5*0.25/24.75
V1 = 0.25L
so,
0.25L volume needed for making 2.5L of methanol 0.25Msolution
To prepare a 2.5 N NaOH solution in methanol, you would first calculate the amount of NaOH needed based on its molar mass and the desired concentration. Then, dissolve this amount of NaOH in the appropriate volume of methanol to make the 2.5 N solution. Be sure to wear appropriate safety gear and follow proper handling procedures when working with NaOH.
To find the grams needed for 5.00 ml of the solution, you can use the formula: mass = volume x density. Simply multiply the volume (5.00 ml) by the density (1.50 g/ml), which gives you 7.50 grams of the solution.
To prepare a 0.1 molar methanolic HCl solution, you would first calculate the amount of hydrochloric acid needed to achieve a concentration of 0.1 moles in 1 liter of methanol. You would then measure out the calculated amount of hydrochloric acid and add it to the methanol in a volumetric flask. Finally, you would top up the flask with methanol to make a final volume of 1 liter and mix well.
The stoichiometric ratio for methanol is 1:1. This means that one mole of methanol reacts with one mole of an oxidizer, such as oxygen, in a complete combustion reaction. This ratio is essential to calculate the amount of reactants needed to ensure complete conversion of methanol to products.
The pKa of methanol is approximately 15.5. This means that methanol is a weak acid. Its pKa value affects its chemical properties by determining its ability to donate a proton in a chemical reaction. Methanol's weak acidity allows it to participate in certain reactions where proton donation is needed, influencing its reactivity and interactions with other substances.
To make a 100 ppm solution of methanol in 100 mL of water, you would need 10 mg of methanol. This is because 100 ppm is equivalent to 100 mg/L, and since you have 100 mL of water, you would need 10 mg of methanol (100 mg/L x 0.1 L).
To prepare a 2.5 N NaOH solution in methanol, you would first calculate the amount of NaOH needed based on its molar mass and the desired concentration. Then, dissolve this amount of NaOH in the appropriate volume of methanol to make the 2.5 N solution. Be sure to wear appropriate safety gear and follow proper handling procedures when working with NaOH.
To find the grams needed for 5.00 ml of the solution, you can use the formula: mass = volume x density. Simply multiply the volume (5.00 ml) by the density (1.50 g/ml), which gives you 7.50 grams of the solution.
To prepare a 0.1 molar methanolic HCl solution, you would first calculate the amount of hydrochloric acid needed to achieve a concentration of 0.1 moles in 1 liter of methanol. You would then measure out the calculated amount of hydrochloric acid and add it to the methanol in a volumetric flask. Finally, you would top up the flask with methanol to make a final volume of 1 liter and mix well.
The stoichiometric ratio for methanol is 1:1. This means that one mole of methanol reacts with one mole of an oxidizer, such as oxygen, in a complete combustion reaction. This ratio is essential to calculate the amount of reactants needed to ensure complete conversion of methanol to products.
I cannot answer this question.
The pKa of methanol is approximately 15.5. This means that methanol is a weak acid. Its pKa value affects its chemical properties by determining its ability to donate a proton in a chemical reaction. Methanol's weak acidity allows it to participate in certain reactions where proton donation is needed, influencing its reactivity and interactions with other substances.
Mass and volume are needed to calculate the density of a graduated cylinder.
To prepare N-phenylanthranilic acid indicator, dissolve 0.1 g of N-phenylanthranilic acid in 100 ml of ethanol or methanol. This will create a stock solution of the indicator that can be diluted further as needed for specific applications.
To prepare a 10 ppm (parts per million) calibration gas in 100 mL of nitrogen, you need to calculate the amount of methanol required. Since 10 ppm means 10 mg of methanol per liter of gas, for 100 mL (0.1 L), you would need 1 mg of methanol. To achieve this, you can directly weigh out 1 mg of methanol and dilute it in the 100 mL of nitrogen.
TO know about refraction of light and by the way it is still needed.......................
To produce 100.0 kg of methanol, you would need 50.0 kg of carbon monoxide and 150.0 kg of hydrogen. This is because the reaction to produce methanol from carbon monoxide and hydrogen has a 1:3 ratio.