No. Alkoxide ions are stronger bases than hydroxide ions.
The only way of making an alkoxide is by reacting a hihgly reactive metal such as sodium with the corresponding alcohol (react sodium with methanol to produce sodium methoxide).
In water sodium methoxide will react to produce sodium hydroxide and methanol.
The methoxide ion would steal a hydrogen ion from water, forming sodium hydroxide and methanol. CH3ONa + H2O --> CH3OH + NaOH
The formula mass of KCl is 75.5 so when 94.375g of it are dissolved in i litre water the solution prepared is 1.25 molar
No, not any substance, but some, and here's why. Methanol has a density of 0.79g. If you put something in the methanol, say wood (oak), that weighs 0.89g, which is more, it will sink. It all depends on if it weighs more or less than the methanol. If it weighs more, it will sink, If it weighs less, it will float.
Metallic copper does not react with sodium hydroxide. But if sodium hydroxide is added into a solution of copper ions, it would form Copper(II) Hydroxide. It is a precipitate which is insoluble in water.
Sodium Hydroxide is way too basic (very high pH) and would cause internal damage.
Potassium hydroxide is a polar compound. Octane is a non polar compound. Therefore, these compounds would not be dissolved in each other.
The methoxide ion would steal a hydrogen ion from water, forming sodium hydroxide and methanol. CH3ONa + H2O --> CH3OH + NaOH
No, adding solid sodium hydroxide to neutralize hydrochloric acid (HCl) would not cause sodium chloride to redissolve. The reaction between sodium hydroxide and hydrochloric acid forms water and sodium chloride, which remains in its dissolved form. The addition of solid sodium hydroxide would simply further neutralize the acid and increase the concentration of the resulting sodium chloride solution.
If it produces hydroxide ions (OH-) when dissolved in water, it is considered a base. Examples would be sodium hydroxide (NaOH), potassium hydroxide (KOH), and even ammonia (NH3) becauseNH3 + H2O ==> NH4+ + OH-
Step 1:The hydroxide nucleophiles attacks at the electrophilic C ofthe ester C=O, breaking the π bond and creating the tetrahedral intermediate.Step 2:The intermediate collapses, reforming the C=Oresults in the loss of the leaving group the alkoxide, RO-, leading to the carboxylic acid.Step 3:An acid / base reaction. A very rapid equilibrium where the alkoxide,RO- functions as a base deprotonating the carboxylic acid, RCO2H, (an acidic work up would allow the carboxylic acid to be obtained from the reaction).
The formula mass of KCl is 75.5 so when 94.375g of it are dissolved in i litre water the solution prepared is 1.25 molar
Calcium hydroxide is a base; the pH is over 7.
Sodium hydroxide, particularly highly concentrated sodium hydroxide, can dissolve glass if left sitting long enough. Therefore, if you leave the sodium hydroxide in the burette after finishing your titration, you could increase the volume inside the burette from the glass being dissolved from the inside out. This would make the burette measure the titration volume inaccurately and would invalidate the results of future titrations done with this instrument.
The solubility of cholesterol in methanol is 0.014. 2-propanol would be a better solvent than methanol for the extraction of cholesterol from egg yolk.
To neutralise a strong acid, you would need a strong alkali (or lots of a weak alkali, but that would be impractical). Potassium hydroxide, sodium hydroxide, lithium hydroxide, calcium hydroxide, calcium hydroxide and magnesium hydroxide would all work.
Zippo does not sell a lighter that has a green flame. In order to achieve a green flame, you'd have to use chemicals such as Copper Sulfate or Boric Acid dissolved in methanol. You would take the Chemical and Methanol solution and add it to your lighter fluid. Another option is to have a piece of copper such as a wire suspended in your flame. It is best to sand the piece of copper.
Methanol has a tetrahedral shape. Oxygen by itself would have a bent shape when bonded with hydrogen and carbon