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How Many Moles Of PCl5 Can Be Produced From 58.0 G Of Cl2 (and Excess P4)?
To determine how many moles of PCl5 can be produced from 58.0 g of Cl2, we first need to calculate the moles of Cl2. The molar mass of Cl2 is approximately 70.9 g/mol, so the number of moles of Cl2 is 58.0 g / 70.9 g/mol ≈ 0.819 moles. The balanced reaction for the formation of PCl5 from P4 and Cl2 is: P4 + 10 Cl2 → 4 PCl5. From this, we see that 10 moles of Cl2 produce 4 moles of PCl5, so 0.819 moles of Cl2 can produce (0.819 moles Cl2) * (4 moles PCl5 / 10 moles Cl2) ≈ 0.3276 moles of PCl5. Thus, approximately 0.328 moles of PCl5 can be produced.
How many moles of H2O are required for the reaction of 0.24 moles of Ci2?
To determine the moles of H2O required for the reaction with 0.24 moles of Cl2, we first need the balanced chemical equation. For example, in the reaction of chlorine gas with water, Cl2 + H2O → HCl + HOCl, one mole of Cl2 reacts with one mole of H2O. Therefore, 0.24 moles of Cl2 would require 0.24 moles of H2O.
How many moles of Na are there in 5 moles NaCl?
There are 5 formula masses of Na in 5 formula masses of NaCl, as indicated by the fact that the symbol for sodium has no explicit subscript in the formula of NaCl. Neither sodium nor sodium chloride has moles in the strictest sense, since neither of them is covalently bonded.
How many milliliters of Cl2 gas must you have to obtain 0.30g at STP in chemistry?
You can use the ideal gas law to solve this problem. First, convert 0.30 g of Cl2 to moles. Then use the molar volume of gas at STP (22.4 L/mol) to determine the volume of Cl2 gas needed. Convert this volume to milliliters (1 L = 1000 mL) to find the answer.
How many moles of Cl are in a sample that contains 10.0 moles C2HCl3?
it wouldn't be moles of Cl it would be Cl2 as chlorine doesn't exist as an atom it exsists as two joined to form a compound this is very easy stuff the answer is 15 moles of Cl2 as there 30 moles of Cl hope this helps learn your moles it's easy stuff
How many grams cl2 needed to produce 1.5 moles of chloroform?
To produce 1.5 moles of chloroform (CHCl3), you would need 3 moles of chlorine (Cl2) as the reaction is 1:1 between Cl2 and CHCl3. The molar mass of Cl2 is approximately 70.9 g/mol, so 3 moles of Cl2 would be 3 * 70.9 g. Therefore, you would need approximately 212.7 grams of Cl2.
How Many Moles Of PCl5 Can Be Produced From 58.0 G Of Cl2 (and Excess P4)?
To determine how many moles of PCl5 can be produced from 58.0 g of Cl2, we first need to calculate the moles of Cl2. The molar mass of Cl2 is approximately 70.9 g/mol, so the number of moles of Cl2 is 58.0 g / 70.9 g/mol ≈ 0.819 moles. The balanced reaction for the formation of PCl5 from P4 and Cl2 is: P4 + 10 Cl2 → 4 PCl5. From this, we see that 10 moles of Cl2 produce 4 moles of PCl5, so 0.819 moles of Cl2 can produce (0.819 moles Cl2) * (4 moles PCl5 / 10 moles Cl2) ≈ 0.3276 moles of PCl5. Thus, approximately 0.328 moles of PCl5 can be produced.
When 4 moles of aluminum are allowed to react with an excess of chlorine gas CL2 how many moles of aluminum chlorde are produced?
When 4 moles of aluminum react with an excess of chlorine gas (Cl2), 4 moles of aluminum chloride are produced because the balanced chemical equation for this reaction is: 2 Al + 3 Cl2 -> 2 AlCl3 Since the mole ratio between aluminum and aluminum chloride is 2:2, it means that for every 2 moles of aluminum, 2 moles of aluminum chloride are produced.
What mass of chlorine gas will react with 92 grams of sodium?
The balanced chemical equation for the reaction between chlorine gas and sodium is: 2Na + Cl2 -> 2NaCl Using the equation, we can see that 1 mole of chlorine gas (Cl2) reacts with 2 moles of sodium (2Na). To calculate the mass of chlorine gas needed to react with 92 grams of sodium, first convert 92 grams of sodium to moles, then use the mole ratio from the balanced equation to find the moles of chlorine gas needed. Finally, convert the moles of chlorine gas to grams.
How many moles of cl2 are there in 7.1g of chlorine?
To find the number of moles of Cl2 in 7.1g of chlorine, you need to divide the mass of Cl2 by its molar mass. The molar mass of Cl2 is 70.9 g/mol. Therefore, 7.1g / 70.9 g/mol = 0.1 moles of Cl2.
When 4 moles of aluminum are allowed to react with an excess of chlorine gas Cl2 how many moles of aluminum chloride are produced?
When 4 moles of aluminum react with an excess of chlorine gas, 4 moles of aluminum chloride are produced. This is because the balanced chemical equation for the reaction is: 2Al + 3Cl2 -> 2AlCl3 This means that 2 moles of aluminum react with 3 moles of chlorine gas to produce 2 moles of aluminum chloride, so 4 moles of aluminum will produce 4 moles of aluminum chloride.
How much heat is needed to make 2.00 moles of Cl2 gas?
The necessary heat to transform liquid chlorine (Cl2) to a gas is 9,756 kcal.
How many moles of O2 must react with elemental chlorine to produce 69.1 moles of dichlorine heptoxide?
2Cl2 + 7O2 --> 2Cl2O7So for every 2 moles of dichlorine heptoxide formed, 7 moles of oxygen are reacted.69.1 moles Cl2O7 * (7 moles O2 / 2 moles Cl2O7) = 241.85 moles O2
How many moles in 79.3g CL2?
To find the number of moles in 79.3g of Cl2, first determine the molar mass of Cl2 (35.5g/mol x 2 = 71g/mol). Next, divide the given mass by the molar mass to get the number of moles (79.3g / 71g/mol = 1.12 moles of Cl2).
What reactant is limiting if 3000 cm3 of Cl2 at STP react with a solution containing 25 grams of NaBr?
Cl2 + 2NaBr => Br2 + 2NaCl One mole Cl2 reacts with 2 moles NaBr Cl2 = 71 NaBr = 102.9 Molar volume = 22.414 L/mole for ideal gas @STP 3L Cl2 = 3/22.414 = 0.1338 mole 25g NaBr = 25/102.9 = 0.2430 mole 0.1338 moles Cl2 requires 0.2676 moles NaBr for complete reaction The NaBr is the limiting reagent
How many mole of HCL will be required to react with potassium heptaoxodichromateiv to produce 3 moles of chlorine?
Six moles of HCl will be required: Each mole of chlorine contains two chlorine atoms, but each mole of HCl contains only one chlorine atom and the other reagent noted contains no chlorine atoms.
How many moles of Na are there in 5 moles NaCl?
There are 5 formula masses of Na in 5 formula masses of NaCl, as indicated by the fact that the symbol for sodium has no explicit subscript in the formula of NaCl. Neither sodium nor sodium chloride has moles in the strictest sense, since neither of them is covalently bonded.
