To find the number of moles of Cl2 in 7.1g of chlorine, you need to divide the mass of Cl2 by its molar mass. The molar mass of Cl2 is 70.9 g/mol. Therefore, 7.1g / 70.9 g/mol = 0.1 moles of Cl2.
Since chlorine gas is a diatomic molecule (Cl2), one mole of chlorine gas contains two moles of chlorine atoms. Therefore, 6.00 moles of chlorine atoms would be equivalent to 3.00 moles of chlorine gas.
To calculate the number of moles in 140 g of Cl2, divide the given mass by the molar mass of Cl2. Number of moles = Mass / Molar mass = 140 g / 70.9 g/mol = 1.97 moles. Therefore, there are 1.97 moles of chlorine gas in 140 g of Cl2.
To calculate the number of moles in 15g of chlorine gas, you need to use its molar mass. The molar mass of chlorine is approximately 35.5 g/mol. Divide the given mass by the molar mass to find the number of moles. For 15g of chlorine gas, you will have about 0.42 moles.
To produce 1.5 moles of chloroform (CHCl3), you would need 3 moles of chlorine (Cl2) as the reaction is 1:1 between Cl2 and CHCl3. The molar mass of Cl2 is approximately 70.9 g/mol, so 3 moles of Cl2 would be 3 * 70.9 g. Therefore, you would need approximately 212.7 grams of Cl2.
The molar mass of chlorine gas (Cl2) is 70.91 g/mol. To convert grams to moles, you divide the mass (84 g) by the molar mass (70.91 g/mol). So, 84 grams of chlorine gas is equal to approximately 1.18 moles.
To find the number of moles in 79.3g of Cl2, first determine the molar mass of Cl2 (35.5g/mol x 2 = 71g/mol). Next, divide the given mass by the molar mass to get the number of moles (79.3g / 71g/mol = 1.12 moles of Cl2).
Since chlorine gas is a diatomic molecule (Cl2), one mole of chlorine gas contains two moles of chlorine atoms. Therefore, 6.00 moles of chlorine atoms would be equivalent to 3.00 moles of chlorine gas.
To calculate the number of moles in 140 g of Cl2, divide the given mass by the molar mass of Cl2. Number of moles = Mass / Molar mass = 140 g / 70.9 g/mol = 1.97 moles. Therefore, there are 1.97 moles of chlorine gas in 140 g of Cl2.
4.005
9.02 X 10^23 atoms Cl2 (1mol Cl2/6.022 X 10^23) = 1.50 moles Cl2
You cannot produce any Iodine from chlorine, because chlorine (Cl2, gas) is an element, hence it does not contain any Iodine (I2, solid with purple vapor). However when 8.00 moles Cl2 react with excess (>16) moles potassium Iodide (KI) then also 8.00 moles of Iodine are produced, not FROM but BY MEANS OF chlorine. Cl2 + 2KI --> 2 KCl + I2
To calculate the number of moles in 15g of chlorine gas, you need to use its molar mass. The molar mass of chlorine is approximately 35.5 g/mol. Divide the given mass by the molar mass to find the number of moles. For 15g of chlorine gas, you will have about 0.42 moles.
To produce 1.5 moles of chloroform (CHCl3), you would need 3 moles of chlorine (Cl2) as the reaction is 1:1 between Cl2 and CHCl3. The molar mass of Cl2 is approximately 70.9 g/mol, so 3 moles of Cl2 would be 3 * 70.9 g. Therefore, you would need approximately 212.7 grams of Cl2.
The molar mass of chlorine gas (Cl2) is 70.91 g/mol. To convert grams to moles, you divide the mass (84 g) by the molar mass (70.91 g/mol). So, 84 grams of chlorine gas is equal to approximately 1.18 moles.
To determine the moles of H2O required for the reaction with 0.24 moles of Cl2, we first need the balanced chemical equation. For example, in the reaction of chlorine gas with water, Cl2 + H2O → HCl + HOCl, one mole of Cl2 reacts with one mole of H2O. Therefore, 0.24 moles of Cl2 would require 0.24 moles of H2O.
When 4 moles of aluminum react with an excess of chlorine gas (Cl2), 4 moles of aluminum chloride are produced because the balanced chemical equation for this reaction is: 2 Al + 3 Cl2 -> 2 AlCl3 Since the mole ratio between aluminum and aluminum chloride is 2:2, it means that for every 2 moles of aluminum, 2 moles of aluminum chloride are produced.
To determine how many moles of PCl5 can be produced from 58.0 g of Cl2, we first need to calculate the moles of Cl2. The molar mass of Cl2 is approximately 70.9 g/mol, so the number of moles of Cl2 is 58.0 g / 70.9 g/mol ≈ 0.819 moles. The balanced reaction for the formation of PCl5 from P4 and Cl2 is: P4 + 10 Cl2 → 4 PCl5. From this, we see that 10 moles of Cl2 produce 4 moles of PCl5, so 0.819 moles of Cl2 can produce (0.819 moles Cl2) * (4 moles PCl5 / 10 moles Cl2) ≈ 0.3276 moles of PCl5. Thus, approximately 0.328 moles of PCl5 can be produced.