You cannot produce any Iodine from chlorine, because chlorine (Cl2, gas) is an element, hence it does not contain any Iodine (I2, solid with purple vapor).
However when 8.00 moles Cl2 react with excess (>16) moles potassium Iodide (KI) then also 8.00 moles of Iodine are produced, not FROM but BY MEANS OF chlorine.
Cl2 + 2KI --> 2 KCl + I2
When 4 moles of aluminum react with an excess of chlorine gas, 4 moles of aluminum chloride are produced. This is because the balanced chemical equation for the reaction is: 2Al + 3Cl2 -> 2AlCl3 This means that 2 moles of aluminum react with 3 moles of chlorine gas to produce 2 moles of aluminum chloride, so 4 moles of aluminum will produce 4 moles of aluminum chloride.
The number of chlorine atoms in 2,00 moles of CCl4 is 48,113.10e23.
The balanced chemical equation for the reaction between aluminum and chlorine is 2Al + 3Cl2 -> 2AlCl3. This means that for every 2 moles of aluminum that react, 2 moles of aluminum chloride are produced. Therefore, if 0.440 mol of aluminum is used, it will produce 0.440 mol of aluminum chloride.
The atomic mass of hydrogen is 1.008 and that for chlorine is 35.45. The moles of hydrogen available are therefore 0.490/1.008 = 0.486 and the moles of chlorine available, 50/35.45, are greater than 1. Each molecule of hydrogen chloride requires one atom each of chlorine and hydrogen. Therefore, with the specified conditions, hydrogen is stoichiometrically limiting, and 0.486 moles of HCl can be made.
There is one mole of iodine in one mole. There are 126.90447grams of iodine in one mole. There are also 6.022x1023 atoms in one mole.
When salt (NaCl) is split by electrolysis, one mole of sodium (Na) and one mole of chlorine (Cl2) gas are produced. The molar mass of NaCl is 58.44 g/mol, so 40.0 g of NaCl is approximately 0.68 moles. Therefore, 0.68 moles of chlorine gas are produced.
When 4 moles of aluminum react with an excess of chlorine gas, 4 moles of aluminum chloride are produced. This is because the balanced chemical equation for the reaction is: 2Al + 3Cl2 -> 2AlCl3 This means that 2 moles of aluminum react with 3 moles of chlorine gas to produce 2 moles of aluminum chloride, so 4 moles of aluminum will produce 4 moles of aluminum chloride.
222,6 grams of iodine is equivalent to 1,754 moles.
When 4 moles of aluminum react with an excess of chlorine gas (Cl2), 4 moles of aluminum chloride are produced because the balanced chemical equation for this reaction is: 2 Al + 3 Cl2 -> 2 AlCl3 Since the mole ratio between aluminum and aluminum chloride is 2:2, it means that for every 2 moles of aluminum, 2 moles of aluminum chloride are produced.
The number of chlorine atoms in 2,00 moles of CCl4 is 48,113.10e23.
How many moles of NH3 are produced when 1.2 mol of nitrogen reacts with hydrogen?
In hydrochloric acid (HCl), there is one mole of chlorine for every mole of hydrochloric acid. Therefore, in 3.4 moles of hydrochloric acid, there are also 3.4 moles of chlorine.
The balanced equation for the reaction between Iodine and Hydrogen is: H2 + I2 --> 2HI The ratio of I2 to HI is 1:2 Therefore 1 mole of Iodine can form a maximum of 2 moles of Hydrogen Iodide
The balanced chemical equation for the reaction between aluminum and chlorine is 2Al + 3Cl2 -> 2AlCl3. This means that for every 2 moles of aluminum that react, 2 moles of aluminum chloride are produced. Therefore, if 0.440 mol of aluminum is used, it will produce 0.440 mol of aluminum chloride.
The atomic mass of hydrogen is 1.008 and that for chlorine is 35.45. The moles of hydrogen available are therefore 0.490/1.008 = 0.486 and the moles of chlorine available, 50/35.45, are greater than 1. Each molecule of hydrogen chloride requires one atom each of chlorine and hydrogen. Therefore, with the specified conditions, hydrogen is stoichiometrically limiting, and 0.486 moles of HCl can be made.
Since chlorine gas is a diatomic molecule (Cl2), one mole of chlorine gas contains two moles of chlorine atoms. Therefore, 6.00 moles of chlorine atoms would be equivalent to 3.00 moles of chlorine gas.
To find the number of moles of atoms in 75.10 grams of chlorine, you need to first determine the molar mass of chlorine. Chlorine has a molar mass of approximately 35.45 g/mol. Next, you can use the formula Moles = Mass / Molar Mass to calculate the moles of chlorine atoms in 75.10 grams. This would result in approximately 2.12 moles of chlorine atoms.