There are 5 formula masses of Na in 5 formula masses of NaCl, as indicated by the fact that the symbol for sodium has no explicit subscript in the formula of NaCl. Neither sodium nor sodium chloride has moles in the strictest sense, since neither of them is covalently bonded.
To calculate the grams of NaCl needed to make a 0.125 M solution in 200.0 mL, use the formula: moles = Molarity x Volume (L). First, convert 200.0 mL to 0.2 L. Then, calculate moles: 0.125 mol/L x 0.2 L = 0.025 moles of NaCl. Finally, convert moles to grams by multiplying by the molar mass of NaCl (58.44 g/mol): 0.025 moles x 58.44 g/mol = 1.46 grams of NaCl.
The limiting reagent in a reaction is the reactant that runs out first. For example, if you are reacting 10 moles of HCl and 5 moles of NaOH, you will get 5 moles of H20, 5 moles of NaCl, and 5 moles of HCl, because the remaining HCl had nothing to react with. Therefore, the NaOH is the limiting reagent.
The nunber of moles of oxygen is 2,5.
The answer is 10 moles of carbon monoxide.2 C + O2 = 2 CO
In 5 moles of octane, C8H18, there are 40 moles of carbon atoms (5 moles octane x 8 carbon atoms) and 90 moles of hydrogen atoms (5 moles octane x 18 hydrogen atoms).
Based on the stoichiometry of NaCl, for every one mole of NaCl there is one mole of Na+ and one mole of Cl-. Therefore, there are 2.5 moles Na+ and 2.5 moles Cl-, totaling 5 moles of ions altogether.
For this you need the atomic mass of Na. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel.11.5 grams Na / (23.0 grams) = .500 moles Na
1 mole of Sodium Chloride weighs 58.5 grams (1 mole is the same as the molecular weight of a compound. The molecular mass of Sodium Chloride- NaCl is 23 [Na atomic mass] + 35.5 [Cl atomic mass] which is equal to 58.5 grams).Thus 10 moles would weigh 10x58.5 grams = 585 grams.The answer is 585 grams.
5 moles of NaCl have 292,2 g.
5 x 0.25 = 1.25 moles
5 grams of table salt is 5 grams of NaCl. NaCl has a molar mass of 58.443 grams/mol, so 5 grams would be .0855 mol NaCl. In one mole of NaCl there is one mole of Na, so there would be .0855 mol Na, or 5.235 * 1022 atoms Na.
You haven't given the volume of solution. M means moles per liter. First off you divide 5 by 1000 and multiply by the amount of mls you have to find out how many moles that you have. then multiply by molecular weight of NaCl
The total ionic equation for NaCl + AgNO3 is: Na⁺ + Cl⁻ + Ag⁺ + NO₃⁻ → AgCl + Na⁺ + NO₃⁻
1 teaspoon of salt (NaCL) = 6 grams of NaCL or 2,360 mg of sodium (Na). (Na molecular wt is 23, Cl is 35.5, so NaCl is 58.5, so Na is 40 % times grams of wt of NaCl.) So 1 gram NaCl X 1 tsp/6 g NaCl = 0.16667 tsp NaCl or if you want Sodium ( how salt is expressed on food labels) then 1 gram of Na X 1 tsp NaCl/2.360 gram Na = 0.42 tsp Na.
The answer is 0,86 meq.
To find the number of grams in 0.350 moles of Na, you need to multiply the number of moles by the molar mass of Na. The molar mass of Na is 22.99 g/mol. So, 0.350 moles of Na * 22.99 g/mol = 8.0465 grams of Na.
the molar mass of sodium is 23 and chlorine is 35 so they add together to create 58 grams per mole. So 5.58g/58g=.0962 moles.