The answer is 0,86 meq.
There are 150 mg of Na in 1 ml of 0.9% NaCl solution. This is equivalent to 150 mEq of Na in 150 ml of the same solution.
The cation, or positively charged ion, in NaCl is Na+.
The equation is: NaCl----------Na++ Cl-
NaCl---------------→Na+ + Cl-
Na+ + Cl- --> NaCl NaCl = salt.
NaCl --> Na+ + Cl- You could write water on either side I suppose, but it is negligible. I've also seen H2O written over the arrow.
5 grams of table salt is 5 grams of NaCl. NaCl has a molar mass of 58.443 grams/mol, so 5 grams would be .0855 mol NaCl. In one mole of NaCl there is one mole of Na, so there would be .0855 mol Na, or 5.235 * 1022 atoms Na.
To convert milliequivalents (mEq) of an electrolyte to milligrams, you need to know the atomic weight of the element. For example, for sodium (Na), 1 mEq is approximately 23 mg. So, if you have 40 mEq of sodium, it would be around 920 mg.
Pure solide NaCl is not electrically conductive. The water solution of NaCl is an electrolyte and is conductive.
[348 (g NACl)] * [23 (g/mol Na)] * [1 (mol NaCl/mol Na)] / [58.5 (g/mol NaCl)] = [348*23/58.5] = 136.8 = 137 g Na
Since NaCl is composed of one Na atom and one Cl atom, and the molar mass of Na is roughly 23 g/mol while that of Cl is about 35.5 g/mol, the molar mass of NaCl is approximately 58.5 g/mol. In 100 ppm NaCl, there are 100 mg of NaCl in 1 kg of solution. Therefore, the amount of Na in 100 ppm NaCl would be 100 mg * (23 g Na / 58.5 g NaCl) = ~ 39.3 ppm Na.
No, a 100 ppm NaCl solution means there are 100 parts per million of NaCl (sodium chloride) in the solution, not just sodium (Na) alone. To calculate the amount of sodium ions (Na+) in the solution, you would need to consider the molar mass of NaCl and the percentage of Na+ in NaCl.