NaCl --> Na+ + Cl-
You could write water on either side I suppose, but it is negligible.
I've also seen H2O written over the arrow.
The equation is: NaCl----------Na++ Cl-
An example of an ionic equation is: NaCl(s) -> Na+(aq) + Cl-(aq) This equation shows the dissociation of solid sodium chloride into its ions sodium and chloride in an aqueous solution.
An example is the dissociation of NaCl in water: NaCl (s) -> Na+ (aq) + Cl- (aq). Here, NaCl breaks apart into its constituent ions, Na+ and Cl-, when dissolved in water due to the attraction between the ions and water molecules.
The balanced ionic equation for sodium chloride (NaCl) in water (H2O) is: NaCl (s) → Na+ (aq) + Cl- (aq) This equation shows the dissociation of sodium chloride into its ions sodium (Na+) and chloride (Cl-) in water.
Dissociation of sodium chloride in water solution: NaCl -----------Na+ + Cl-
The dissociation equation for sulfuric acid (H2SO4) is: H2SO4 - 2H SO42-
the solid on the left side and aqueous ions on the right side.
The equation for the dissociation of water is: H2O ↔ H+ + OH-
The balanced equation for the dissociation of water is: 2H2O (liquid) ⇌ 2H+ (aqueous) + O2- (aqueous)
The dissociation equation for zinc fluoride (ZnF2) in water is: ZnF2 (s) → Zn2+ (aq) + 2F- (aq)
The dissociation equation for CaCl2 in water is: CaCl2 (s) → Ca2+ (aq) + 2Cl- (aq)
The dissociation equation for potassium chromate (K2CrO4) in water is: K2CrO4(s) -> 2K+(aq) + CrO4^2-(aq).