For this you need the Atomic Mass of Na. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel.
11.5 grams Na / (23.0 grams) = .500 moles Na
The formula for methane shows that each molecule of it contains 5 atom: 1 carbon atom and 4 hydrogen atoms. The gram molecular mass of methane is 16.04. Therefore, 28 grams of methane contains 28/16.04 moles of methane and 5 times this number, or 8.7, "moles of atoms", to the justified number of significant digits.
That would be 3,487.05 grams.
5.5 pounds = 2495 grams.
4 mol over 0.800 kg
5 grams.
5 moles of NaCl have 292,2 g.
You haven't given the volume of solution. M means moles per liter. First off you divide 5 by 1000 and multiply by the amount of mls you have to find out how many moles that you have. then multiply by molecular weight of NaCl
There are 5 formula masses of Na in 5 formula masses of NaCl, as indicated by the fact that the symbol for sodium has no explicit subscript in the formula of NaCl. Neither sodium nor sodium chloride has moles in the strictest sense, since neither of them is covalently bonded.
1 mole of Sodium Chloride weighs 58.5 grams (1 mole is the same as the molecular weight of a compound. The molecular mass of Sodium Chloride- NaCl is 23 [Na atomic mass] + 35.5 [Cl atomic mass] which is equal to 58.5 grams).Thus 10 moles would weigh 10x58.5 grams = 585 grams.The answer is 585 grams.
To calculate the grams of NaCl needed to make a 0.125 M solution in 200.0 mL, use the formula: moles = Molarity x Volume (L). First, convert 200.0 mL to 0.2 L. Then, calculate moles: 0.125 mol/L x 0.2 L = 0.025 moles of NaCl. Finally, convert moles to grams by multiplying by the molar mass of NaCl (58.44 g/mol): 0.025 moles x 58.44 g/mol = 1.46 grams of NaCl.
the molar mass of sodium is 23 and chlorine is 35 so they add together to create 58 grams per mole. So 5.58g/58g=.0962 moles.
The answer is 1,98 g sodium.
Based on the stoichiometry of NaCl, for every one mole of NaCl there is one mole of Na+ and one mole of Cl-. Therefore, there are 2.5 moles Na+ and 2.5 moles Cl-, totaling 5 moles of ions altogether.
5 x 0.25 = 1.25 moles
Molarity = moles of solute/volume of solution Find moles NaCl 55 grams NaCl (1mol NaCl/58.44 grams) = 0.941 moles NaCl Molarity = 0.941 moles NaCl/35 Liters = 0.027 Molarity NaCl ( sounds reasonable as 55 grams is not much in 35 Liters of water, which would be about 17.5 2 liter sodas )
There are 5 moles of calcium in 200 grams of calcium. This calculation is based on the molar mass of calcium, which is approximately 40 grams per mole.
5 moles of lead is equal to 1 036 g.